Answer:
sigma bond and represent two electrons
<span>The answer I think is, 7.83E22.</span>
Answer:
The answer to the question is;
The concentration of the Solution #1 in terms of molarity is
0.16704X moles/litre.
Explanation:
Let the concentration of the stock solution be X moles/liter
Therefore, 83.52 ml of the stock solution contains
83.52×(X/1000) moles
Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of
500 ml of solution 1 contains 83.52×(X/1000) moles
Therefore 1000 ml or 1 litre contains 2×83.52×(X/1000) moles = 0.16704X moles/litre
The molarity of solution 1 is 0.16704X moles/litre.
(a) The molecular shapes of cis and Trans forms of N2F2 are-
b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.
In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.
In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.
Thus: trans N2F2 is non polar molecule.