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3 years ago

Why do gems have different properties as metals? Ready? Enter your answer here

Chemistry

1 answer:

dusya [7]3 years ago

8 0

The gems are more colorful and a little more crystalline shape. Metals conduct electricity but sometimes gems don’t.

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Hydrocarbon weighing 112g is burned in air to produce 328.5 g of carbon dioxide what percent mass of carbon in the hydrocarbon

Lemur [1.5K]

Answer:

80.0 %

Explanation:

As per the law of conservation of mass all the mass of carbon present in the hydrocarbon weighing 112 g is present in the 328.5 g of carbon dioxide produced when the hydrocarbon was burned in air.

1) Calculate the mass of carbon in 328.5 g of carbon dioxide:

Chemical formula of carbon dioxide: CO₂

Molar mass of CO₂: 12.011 g/mol + 2 × 15.999 g/mol = 44.009 g/mol

Mass of C: x

x / 328.5 g CO₂ = 12.011 g C / 44.009 g/mol ⇒ x = 86.65 g C

2) Calculate the percent mass of carbon:

% = (mass of carbon / mass of carbon dioxide) × 100 =

= (89.65 / 112) × 100 = 80.04%

Round to three signifcant figures: 80.0%.

3 0

4 years ago

A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3

IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cl₂: 4 moles
P: 2 moles
PCl₃: 1 mole
PCl₅: 1 mole

The molar mass of the compounds is:

Cl₂: 70.9 g/mole
P: 31 g/mole
PCl₃: 137.35 g/mole
PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
P: 2 moles× 31 g/mole= 62 grams
PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

$mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}$

mass of Cl₂= 96.97 grams

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

$mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}$

mass of PCl₃= 38.26 grams

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

Learn more with this examples:

4 0

3 years ago

What does the atomic number of an element refer to on the periodic table?

jekas [21]

The elements are listed in order of increasing the atomic number. Its the number that is the number of protons in the nucleus of an atom.

6 0

3 years ago

Read 2 more answers

using the equaation 2h2+o2-->2h2o if 10.0g of hydrogen are used in the presence of excess oxygen how many grams of water will

astra-53 [7]

Answer:

90g of H2O

Explanation:

2H2 + O2 —> 2H2O

First, we calculate the molar masses of H2 And H20.

Molar Mass of H2 = 2g/mol

Mass conc of H2 from the balanced equation = 2 x 2 = 4g

Molar Mass of H2O = 2 + 16 = 18g/mol

Mass conc of H2O from the balanced equation = 2x18 = 36g

From the equation,

4g of H2 produced 36g of H2O

Therefore, 10g of H2 will be produce = (10x36)/4 = 90g of H2O

7 0

3 years ago

What is the measurement?

Lady bird [3.3K]

Pretty sure it's 5.25Explanation:

3 0

3 years ago