Answer:
1.53 L
Explanation:
Step 1: Given data
- Mass of oxygen (m): 11.2 g
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
11.2 g × (1 mol/32.00 g) = 0.350 mol
Step 3: Calculate the volume of oxygen
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm
V = 1.53 L
Na3PO4 + 3 KOH = 3 NaOH + K3PO4
Agar is extracted from an algae (agarophytes, <span>belong to the </span>Rhodophyta (red algae) phylum, <span>primarily from the </span>genera Gelidium<span> and </span><span>Gracilaria</span>).
Agar <span>or </span>agar-agar is a jelly-like substance. Agar is the mixture of two components, agaropectin (D-glucuronic acid and pyruvic acid) and <span>the polysaccharide agarose.</span>
The solution 550 ml total and first we will find the amount of alcohol. 3% = 0.03 550 ml x .03 = 16.5 ml alcohol
Then to find the amount of water used, we just have to subtract the amount of alcohol from the total volume
550 ml total - 16.5 ml alcohol = 533.5 ml water
