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Stels [109]
3 years ago
14

The specific gravity of water is 1.0. True False

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
5 0
The specific gravity of water is 1.0 True 
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(picture is a pic of cute colorful birds c: ) Suppose that you and a friend see brightly colored pigeons like these at a nature
ella [17]

Answer:

It is most definitely not a scientific theory. When you eat, say, blueberries for example, do you turn blue? No. It has to do with their genetic makeup, so their parents must have been fun colors.

Explanation:

8 0
3 years ago
Read 2 more answers
LiNO3(aq) and Na2CO3(aq).If a solid forms when solutions containing these salts are mixed, write the ionic equation.
Alborosie

    The  ionic   equation  is as below


2Li + (aq)  +   CO₃²-<em> </em> →  Li₂CO₃ (s)


explanation

step 1:  write the   molecular  equation  

  2 LiNO₃ (aq)  + Na₂CO₃  (aq) →   Li₂CO₃ (s)   +2NaNO₃

Step 2 :  break  the soluble electrolyte  in ions

2 Li⁺ (aq)  +2NO₃⁻(aq) +  2Na⁺(aq)  + CO₃²⁻ (aq)  → Li₂CO₃  + 2Na⁺(aq)  +2NO₃⁻(aq)


cancel the   spectator  ion  (  2Na⁺ and 2No₃⁻)


The ionic  equation  is therefore

2Li⁺ (aq)  + CO₃²⁻(aq) →  Li₂CO₃ (s)



6 0
3 years ago
Read 2 more answers
thank you so much for helping me I don't know science that well trying to get better I've been getting better good grades but st
Rasek [7]

there is not enough information to make a prediction as we dont know what side she taped on magnet C

5 0
3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
You have 125.0 mL of a solution of H3PO4, bu you don't know its concentration. if you titrate the solution with a 4.56-M solutio
irakobra [83]

Answer:

4.90 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 125.0 mL

M₂ = 4.56 M

V₂ = 134.1 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂  

Substituting the respective values ,  

M₁ *  125.0 mL = 4.56 M *  134.1 mL

M₁ = 4.90 M

6 0
4 years ago
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