The specific gravity of water is 1.0. True False

Is John Cena a rabbit?

Basile [38]

Answer:

Hmm, maybe. We'll never know

Explanation:

5 0

2 years ago

Read 2 more answers

A sample of neon occupies a volume of 478 mL at STP. What will be the volume of the neon when the pressure is reduced to 93.3 kP

Andre45 [30]

The volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

Explanation:

The kinetic theory of gases is mostly based on Boyle's law. From the Boyle's law, the pressure experienced by any gas molecules is inversely proportional to volume of the gas molecules. Also this inverse relation is obeyed if and only if the number of moles and temperature of the gas molecules remained constant.

So, $P=\frac{1}{V}$

So if there is a change in pressure then there will be inverse change in volume. That means if there is decrease in the pressure of gas molecules then there will be increase in the volume and vice versa.

So the Boyle's law is combined as $P_{1} V_{1} = P_{2} V_{2}$

As here the initial pressure or $P_{1}$ is 1 atm or 101.3 kPa and the initial volume is 478 mL. Similarly, the final pressure is 93.3 kPa and the final volume will be

$101.3*10^{3}*478*10^{-3} = 93.3*10^{3} * V_{2}$

$V_{2} = 519 mL$

So, the volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

5 0

3 years ago

Metallic behavior is generally associated with elements with partially filled p orbitals. elements with unpaired electrons. elem

Mila [183]

Answer:

Elements with low ionization energies.

Explanation:

The ionization energy of an atom reffers to the amount of energy that is required to remove an electron from the gaseous form of that atom or ion.

The greater the ionization energy, the more difficult it is to remove an electron. The ionization energybis one of the indicator that shows the reactivity of an element. Elements with a low ionization energy such as metals are usually reffered to as a reducing agents and form cations, this give metals the tendency to

give away their valence electrons when bonding, whereas non-metals tend to take electrons.

Metallic elements have different properties such as shiny, heat and electricity conductivity . They are malleable and ductile Some metals, such as sodium, are soft and can be cut with a knife. while some are very hard such as iron.

4 0

3 years ago

What is an atom? please answer ASAP

Pani-rosa [81]

Answer:

smallest particle of an element which can take part in a chemical reaction

Explanation:

there are atoms of different elements is sodium atom

3 0

3 years ago

Please help I need the answer now. Write a balanced equation for combustion of pentane in plenty supply of air and in limited su

Ratling [72]

Pentane burns in plenty of air: CO₂ and H₂O is produced.

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

Pentane burns in limited amount of air: CO or even C is produced along with H₂O.

2 C₅H₁₂ + 11 O₂ → 10 CO + 12 H₂O

<h3>Explanation</h3>

Pentane is a hydrocarbon. There are five carbon atoms in each of its molecule. Its molecular formula will be C₅H₁₂.

Hydrocarbon fuels burn to produce CO₂ when there's plenty of air.

? C₅H₁₂ + ? O₂ → ? CO₂ + ? H₂O

Among all species in this reaction, C₅H₁₂ has the largest number of atoms per molecule. Assume that the coefficient of C₅H₁₂ is one.

1 C₅H₁₂ + ? O₂ → ? CO₂ + ? H₂O

C₅H₁₂ is the only reactant that contains C atoms. There are 5 C atoms in a C₅H₁₂ molecule. There should be the same number of C atoms in the products.
CO₂ is the only product that contains C atoms. There are one C atom in each CO₂ molecule. 5 C atoms correspond to 5 CO₂ molecules.

1 C₅H₁₂ + ? O₂ → 5 CO₂ + ? H₂O

Similarly, C₅H₁₂ is the only reactant that contains H atoms. H₂O is the only product that contains H atoms. There are 12 H atoms in one C₅H₁₂ molecule, which corresponds to 6 H₂O molecules.

1 C₅H₁₂ + ? O₂ → 5 CO₂ + 6 H₂O

Both CO₂ and H₂O are products that contains O atoms. There are 5 × 2 + 6 × 1 = 16 O atoms in total in 5 CO₂ molecules and 6 H₂O molecules. The 16 O atoms on the product side corresponds to 8 O₂ molecules on the reactant side.

1 C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

1 C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

All coefficients shall be whole numbers. If there's any fraction in this equation, multiply both sides by the least common multiple of their denominators.

Hydrocarbon fuels burn to produce H₂O and CO when there's a limited supply of air. C (soot) might also be produced. Assuming that only CO is produced. Try to balance the equation using the same method.

1 C₅H₁₂ + 11/2 O₂ → 5 CO + 6 H₂O

2 C₅H₁₂ + 11 O₂ → 10 CO + 12 H₂O

Less O₂ is consumed for each mole of C₅H₁₂.

Consider: What would be the balanced equation when only C is produced?

<h3>Reference</h3>

"Products and effects of combustion", GCSE Chemistry (Single Science), BBC Bitesize.

5 0

3 years ago