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Helen [10]
3 years ago
7

Help 6th grade math i will give brainliest

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0
I would say none of the above
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Solve this please<br><img src="https://tex.z-dn.net/?f=4m%20-%205%20%3D%2011" id="TexFormula1" title="4m - 5 = 11" alt="4m - 5 =
krek1111 [17]
M has to equal 2. 11-5 equals 6. 6-4 is 2. 2 is the missing value.
4 0
3 years ago
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Please help me!!!! precalc question
dangina [55]

Step-by-step explanation:

1. Ampltiude is 1

The period is

\frac{2\pi}{3}

is the period

The phase shift is 0

2. The Ampltiude is 2

The period is 2 pi

The phase shift is 1

3. The amplitude is 3

The period is 2 pi/3

The phase shift is -2

4.The amplitude is 2/3

The period is -10pi

The phase shift is 0

5. The Ampltiude is 1

The period is -2 pi

The phase shift is pi

6. The amplitude is 1/4

The period is -4pi

The phase shift is negative 2pi/3

7. The Ampltiude is 3

The period is 4

The phase shift is 8

7 0
3 years ago
Let mZA = 40°. If zB is a complement of ZA, and ZC is a supplement of ZB, find these measures.
seraphim [82]

Angle b= 50

Angle c= 130

Complementary angles are two angles that add to equal 90

Supplementary angles are two angles that add to equal 180

To find the measurement of angle b, subtract 40 from 90 (50)

To find the measurement of angle c, subtract 50 from 180 (130)

7 0
3 years ago
Can someone help me with this, pleasee.
Schach [20]

Answer:

i will say the first one cannot, the second one cannot and the third one can

Step-by-step explanation:

but i am not 100% sure sry

5 0
3 years ago
Read 2 more answers
A particle moves along the x-axis so that at time t≥0t\ge 0t≥0 its position is given by x(t)=−t3+6t2−9t+42.x(t)=-t^3+6t^2-9t+42.
riadik2000 [5.3K]

Answer: 4 units

Step-by-step explanation:

The given position function: x(t)=-t^3+6t^2-9t+42., where t≥0.

To determine:  Total distance traveled by the particle from 0≤ t ≤ 4.0.

At t=0,

x(0)=-(0)^3+6(0)^2-9(0)+42=42\\

At, t=4,

x(4)=-(4)^3+6(4)^2-9(4)+42\\\\=-64+6(16)-36+42=38

Total distance traveled by the particle from 0≤ t ≤ 4.0 = |42-38| units

= 4 units

Hence, the distance traveled by the particle from 0≤t≤4.0 is 4 units.

4 0
3 years ago
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