A. A polynomial of the 5th degree with a leading coefficient of 3 and a constant of 2.

What is the correct first step to solve this system of equations by elimination?

storchak [24]

$\bold{\huge{\pink{\underline{ Solution }}}}$

$\bold{\underline{ Given }}$

We have given two linear equations that is 2x - 3y = -6 and x + 3y = 12 .

$\bold{\underline{ To \: Find }}$

We have to find the value of x and y by elimination method.

$\bold{\underline{ Let's \: Begin }}$

$\sf{ 2x - 3y = -6 ...eq(1)}$

$\sf{ x + 3y = 12 ...eq(2)}$

Multiply eq( 2 ) by 2 :-

$\sf{ 2( x + 3y = 12 )}$

$\sf{ 2x + 6y = 24 }$

Subtract eq(1) from eq(2) :-

$\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}$

$\sf{ 2x + 6y - 2x + 3y = 24 + 6 }$

$\sf{ 9y = 30 }$

$\sf{ y = 30/9}$

$\sf{\red{ y = 10/3}}$

Now, Subsitute the value of y in eq( 1 ):-

$\sf{ 2x - 3(10/3) = -6 }$

$\sf{ 2x - 10 = -6 }$

$\sf{ 2x = -6 + 10}$

$\sf{ x = 4/2}$

$\sf{\red{ x = 2}}$

Hence, The value of x and y is 2 and 10/3

6 0

2 years ago

Please help me complete this !! 12points

Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0

2 years ago

i forgot how to find equivalent fractions. i know that the bottom would be times by 3 to get 18 but if you times 3 by 3 it would

tester [92]

Set up a proportion. take 3/6 = 20/x
Cross multiply 3 * x = 6 * 20
Simplify 3x = 120
Divide by 3 x = 40
So the denominator of the bottom fraction is 40

6 0

3 years ago

Read 2 more answers

It is estimated % of all adults in United States invest in stocks and that % of U.S. adults have investments in fixed income ins

katovenus [111]

Complete question :

It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

Answer:

0.929 ; 0.306

Step-by-step explanation:

Using the information:

P(stock) = P(s) = 28% = 0.28

P(fixed income) = P(f) = 0.85

P(stock and fixed income) = p(SnF) = 26%

a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.

P(F|S) = p(FnS) / p(s)

= 0.26 / 0.28

= 0.9285

= 0.929

(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

P(s|f) = p(SnF) / p(f)

P(S|F) = 0.26 / 0.85 = 0.3058823

P(S¦F) = 0.306 (to 3 decimal places)

3 0

3 years ago

How do you work this out? need help asap

Svetlanka [38]

Hello,

Line 1 is passing through (-4,3), (-2,7) has a slope of (3-7)/(-4+2)=2

Line 2 is passing through (2,9), (4,1) has a slope of (9-1)/(2-4)=-4

One other way:

y=9-1/2 x²
y'=-x

gradient 1=-(-2)=2 for point (-2,7)

gradient 2=-(4)=-4 for point(4,1)

6 0

3 years ago