Answer:
θ = 2 π n_1 + π/2 for n_1 element Z or θ = 2 π n_2 for n_2 element Z
Step-by-step explanation:
Solve for θ:
cos(θ) + sin(θ) = 1
cos(θ) + sin(θ) = sqrt(2) (cos(θ)/sqrt(2) + sin(θ)/sqrt(2)) = sqrt(2) (sin(π/4) cos(θ) + cos(π/4) sin(θ)) = sqrt(2) sin(θ + π/4):
sqrt(2) sin(θ + π/4) = 1
Divide both sides by sqrt(2):
sin(θ + π/4) = 1/sqrt(2)
Take the inverse sine of both sides:
θ + π/4 = 2 π n_1 + (3 π)/4 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
θ = 2 π n_1 + π/2 for n_1 element Z
or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z
Subtract π/4 from both sides:
Answer: θ = 2 π n_1 + π/2 for n_1 element Z
or θ = 2 π n_2 for n_2 element Z
The word algebra originate from baghdad.
Answer:
8/100 is equivalent to 0.08
Hey there!
Let's first find an easier situation.
If we're saying:
How many fives are in ten?
We're doing 10 divided by 5, because we're seeing how many 5's go into 10.
It's no different here.
We will be doing 6 divided by 3/4, just as we did with our simpler situation.
Using our "keep, switch, flip" rule (keep first term, change to multiplication, take reciprocal of second term)
we get:
6 divided by 3/4
=
6 * 4/3
= 24/3
= 8 3/4's in 6.
Hope this helps!
Angle COD equals angle AJL
Angle DCO equals Angle LAJ
Side OC equals side JA is all true expect for the first one
