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Doss [256]
3 years ago
13

Find the wavelength of a photon of light with energy of 9.02x10^-19 J.

Chemistry
1 answer:
vitfil [10]3 years ago
8 0

Answer:

2.21 x 10⁻⁷m⁻¹

Explanation:

Given parameters:

Energy of the photon = 9.02 x 10⁻¹⁹J

Unknown:

Wavelength of the photon = ?

Solution;

The wavelength and energy of a photon are related using the expression below;

       E = \frac{hc}{wavelength}

h is the Planck's constant  = 6.63 x 10⁻⁴m²kg/s²

c is the speed of light

E is the energy

   h c = E x wavelength

   Wavelength = \frac{hc}{E}   = \frac{6.63 x 10^{-34} x 3 x 10^{8}  }{9.02 x 10^{-19} }  

   Wavelength = 2.21 x 10⁻⁷m⁻¹

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4Fe (s) + 3 O2 (g) → 2 Fe2O3 (s)
Novay_Z [31]

Explanation:

The number acquired by an element after the lose or gain of an electron is called oxidation number.

For example, 4Fe(s) + 3O_{2}(g) \rightarrow 2Fe_{2}O_{3}(s)

Here, oxidation number of Fe(s) is 0 and Fe in Fe_{2}O_{3} is +3.

Oxidation number of O in O_{2}(g) is 0 as it is present in its elemental state.

The oxidation number of O in Fe_{2}O_{3} is calculated as follows.

2(3) + 3x = 0\\6 + 3x = 0\\x = \frac{-6}{3}\\= -2

Hence,  oxidation number of O in Fe_{2}O_{3} is -2.

  • The loss of electrons by an element or substance is called oxidation. Here, electrons are being lost by Fe(s) as an increase in oxidation state is occurring. So, Fe(s) is oxidized.
  • The gain of electrons by an element or substance is called reduction. Here, electrons are being added to O_{2} as a decrease in its oxidation state is occurring. So, O_{2}  is reduced.
  • An element or compound which is being reduced is called oxidizing agent. Here, O_{2}  is the oxidizing agent.
  • An element or compound which is being oxidized is called reducing agent. Here, Fe(s) is the reducing agent.
5 0
3 years ago
Which of the following indicates that a chemical change has happened during cooking?
Vera_Pavlovna [14]
The food darkens because the color is changing in the food.
6 0
3 years ago
Which are characteristics of a person who is nearsighted?
Mars2501 [29]

Answer: People that are usually nearsighted have lots of difficulty reading road signs from far distance, also have difficulty with seeing distant objects clearly, and this is obviously something dangerous for a person who has trouble with seeing from far. And the weird thing is, they might have that difficulty but in the other hand, they are able to see very well from close-up tasks such as reading a book or seeing the computer screen clearly. This disability is called "myopia".  In addition, people who are nearsighted also have difficulty seeing objects from far distance very blurry.   Farsightedness is the result of the visual image being focused behind the retina rather than directly on it. It may be caused by the eyeball being too small or the focusing power being too weak.

I hope this helps answer your question! If you have options for this question, let me know k :) (Ask for help too)

6 0
4 years ago
The density of air at ordinary atmospheric pressure and 25 ∘C is 1.19 g/L. What is the mass, in kilograms, of the air in a room
marshall27 [118]
Given:
The density of air = 1.19 g/L at 25°C and atmospheric pressure,
or
density = 1.19 x 10⁻³ kg/L

Volume of air in the room is
V = 12.5*19.5*6.0 = 1462.5 ft³

Note that
1 ft³ = 28.317 L
Therefore
V = (1462.5 ft³)*(28.317 L/ft³) = 4.1414 x 10 ⁴ L

By definition, mass = density*volume.
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(1.19 x 10⁻³ kg/L)*(4.1414 x 10⁴ L) = 49.283 kg

Answer: 49.3 kg (nearest tenth)
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