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Lesechka [4]
1 year ago
13

Assuming acid strength relates directly to number of O atoms bonded to the central atom, rank H₂N₂O₂ [or (HON)₂]; HNO₃ (or HONO₂

); and HNO₂ (or HONO) in order of decreasing acid strength.
Chemistry
1 answer:
Elenna [48]1 year ago
7 0

For Less number of oxygen atoms will be less acidic. Therefore, the rank will be.... So there is 1 oxygen atom bonded to each of the 2 nitrogen atoms.

For HNO3 or {HONO}2. So there are 3 oxygen atoms bonded to the nitrogen.

For HNO2 or HONO. So there are 2 oxygen atoms bonded to the nitrogen.

Less number of oxygen atoms will be less acidic. Therefore, the rank will be...

HNO3>HNO2>H2N2O2

Acid strength is the tendency of an acid, symbolized by the chemical formula, to dissociate into a proton, and an anion, The dissociation of a strong acid in solution is effectively complete, except in its most concentrated solutions.

The strength of a weak organic acid may depend on substituent effects. The strength of an inorganic acid depends on the atom’s oxidation state to which the proton may be attached. Acid strength is solvent-dependent. For example, hydrogen chloride is a strong acid in an aqueous solution but is a weak acid when dissolved in glacial acetic acid.

Learn more about Acid strength here:

brainly.com/question/3223615

#SPJ4

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You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el
Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.  

For example;  

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  It is easier for us to know the highest quantum number from the shell notation:  

        shell notation 1s²2s²2p¹

        highest principal quantum number is 2

  We are left with atomic number 5-2, which is 3

           The element is therefore Li.  

Part A.   5,     30,      58,      56,     99,     79,    19,     98,     9

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Part B.   9,    99,    30,     95,     19,     47,     79

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4 0
3 years ago
Pleasee help <br> will name brainliest
zmey [24]

Answer:

0.125. work- divide the volume value by 1000

873. work- multiply the length value by 100

98100. work- Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 0.981 * 100000

3) Centigram = 98100

285.65. work- 12.5°C + 273.15 = 285.65K

446.85. work- 720K − 273.15 = 446.85°C

346.25. work- 73.1°C + 273.15 = 346.25K

Explanation:

i hope this helps:)  brainliest plss??

8 0
3 years ago
PLEASE HELP QUICK AS POSSIBLE!!!!
GalinKa [24]

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

(1.00*10³g°C)(4.184J/g°C) = 4184J

use sig figs:

4180J

8 0
3 years ago
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