You are given
200 grams of H2O(s) at an initial temperature of 0°C. you are also given the
final temperature of water after heating at 65°C. You are required to get the
total amount of heat to melt the sample. The specific heat capacity, cp, of
water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for
heat, Q, is
Q = m(cp)(T2-T1)
Q = 200g(4.186
J/g-°C )(65°C - 0°C)
<u>Q =
54,418J</u>
Answer:
The answer is:
(a) 
(b) NaCl
(c) 0.211 g
Explanation:
Given:
The mass of NaCl,
= 0.0860 g
The molar mass of NaCl,
= 58.44 g/mol
The volume of 
,
= 30.0 ml
or,
= 0.030 L
Molarity of ,
= 0.050 M
Moles of NaCl will be:
= 
= 
= 
now,
Moles of will be:
(a)
The reaction is:
⇒
(b)
1 mole of NaCl react with,
= 1 mol of
0.0015 mol needs,
= 
Available mol of NaCl < needed amount of NaCl
So,
The limiting reagent is "NaCl".
(c)
The precipitate formed,
= 
= 
The correct option is C.
When glucose is stirred into water to form a solution, then glucose is the SOLUTE and water is the SOLVENT. A solute refers to a substance that is dissolved in a solvent. For instance, salt is the solute that is dissolved in salt solution. A solvent on the other hand refers to the liquid into which the solute was dissolved. For instance, in the case of salt solution, water is the solvent, because it is used to dissolve the salt.
Identifies the number of protons a single atom of the element contains.
The atomic number helps people identify elements according to the number of protons one atom of the element has. It essentially defines the element
