Answer:
-245.7°C es la temperatura del gas bajo 100 torr
Explanation:
Para resolver esta pregunta debemos hacer uso de la ley de Boyle que establece que la presión de un gas es directamente proporcional a la temperatura de este cuando el volumen permanece constante. La ecuación es:
P1T2 = P2T1
<em>Donde P es presión y T temperatura absoluta del estado inicial, 1, y final, 2.</em>
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Reemplazando:
P1 = 1000torr
T2 = ? -Incógnita-
P2 = 100torr
T1 = 273K -Temperatura del hielo fundido = 0°C = 273K
1000torrT2 = 100torr273
T2 = 27.3K
27.3K - 273 =
<h3>-245.7°C es la temperatura del gas bajo 100 torr</h3>
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What invention I want to help you but I am confused
Answer:
18.2 g.
Explanation:
You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:
0.535 g. N2 and 1.984 g. H2
Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.
Answer:
A. There is more dissolved oxygen in colder waters than in warm water.
D. If ocean temperature rise, then the risk to the fish population increases.
Explanation:
Conclusion that can be drawn from the two facts stated above:
*Dissolved oxygen is essential nutrient for fish survival in their aquatic habitat.
*Dissolved oxygen would decrease as the temperature of aquatic habit rises, and vice versa.
*Fishes, therefore, would thrive best in colder waters than warmer waters.
The following are scenarios that can be explained by the facts given and conclusions arrived:
A. There is more dissolved oxygen in colder waters than in warm water (solubility of gases decreases with increase in temperature)
D. If ocean temperature rise, then the risk to the fish population increases (fishes will thrive best in colder waters where dissolved oxygen is readily available).
I have the same question too!!!Dang I thought I would get a answer I just guessed