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3 years ago

Select the electron-domain geometry for a molecule with three bonding domains and one nonbonding domain.

Chemistry

1 answer:

mamaluj [8]3 years ago

6 0

Answer: C) Tetrahedral

Explanation:

The number of electron pairs is 4 that means the hybridization will be $sp^3$ but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be $sp^2$ .

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be $sp^3$ .

Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be $sp^3d$ .

Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be $sp^3d^2$ .

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. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r

Tom [10]

Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

Explanation : Given,

Wavelength = $435.8nm=435.8\times 10^{-9}m$

conversion used : $1nm=10^{-9}m$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength = $435.8\times 10^{-9}m$

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}$

$E=4.56\times 10^{-19}J$

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, $4.56\times 10^{-19}J$

3 0

3 years ago

If heat energy is transferred from direct contact between a warm object and a cold object, it has been transferred by __________

Ganezh [65]

If heat energy is transferred from direct contact between a warm object and a cold object, it has been transferred by Convection.

Heat is transferred through convection, which is the large-scale movement of molecules inside gases and liquids. Conduction is used to move heat from the object to the fluid initially, but fluid motion is responsible for the bulk of the heat transfer.

The transfer of heat between two bodies by currents of moving gas or fluid is known as convection on heat transfer. In free convection, air or water rises and is replaced by a cooler parcel of air or water as it moves away from the hot body.

To learn more about convection please visit -
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4 0

1 year ago

A catalyst decreases the activation energy of a particular exothermic reaction by 34 kJ/mol, to 57 kJ/mol. Assuming that the mec

vagabundo [1.1K]

Answer:

the activation energy for the uncatalyzed reverse reaction is 83kJ/mol

Explanation:

see the attached file

4 0

3 years ago

In general, the more _ a metal has, the stronger its metallic bonds will be because...

Nuetrik [128]

In general, The more valence electrons a metal has, the stronger its metallic bonds will be because Boron is a metalloid and is ionically bonded.it is too electronegative to release its valence electrons for metallic bonding.As a result, their valence electrons feel a stronger pull from the nucleus (a greater effective nuclear charge) and are less easily released for metallic bonding.

5 0

3 years ago

How many grams of HCl(aq) are required to react completely with 1.25g of Zn(s) to form ZnCl2(aq) and H2

faltersainse [42]

1.39 g HCl

Explanation:

The balanced chemical equation for this reaction is given by

Zn(s) + 2HCl(aq) ---> ZnCl2(aq) + H2(g)

Convert the # of grams of Zn to moles:

1.25 g Zn × (1 mol Zn/65.38 g Zn) = 0.0191 mol Zn

Use the molar ratio to find the # of moles of HCl needed to react completely with the given amount of Zn:

0.0191 mol Zn × (2 mol HCl/1 mol Zn) = 0.0382 mol HCl

Convert this amount to grams:

0.0382 mol HCl × (36.458 g HCl/1 mol HCl) = 1.39 g HCl

8 0

3 years ago