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I am Lyosha [343]
3 years ago
8

okay so like i was wondering if ya'll could help with some homework? i have to be somewhere in a little bit and i wanna get this

done before i have to go so i don't have to worry about it later.

Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer:

Im pretty sure the aswer is A

Step-by-step explanation:

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Question 11
shepuryov [24]

Answer:

A. x^27/10

B. 1/x^-27/10

Step-by-step explanation:

Mathematically, if we have the same base, we simply add up the index

Thus, we have that;

x^1/5•x^5/2 = x^(1/5 + 5/2) = x^(2 + 25)/10 = x^27/10

A) In the first form, we have that;

x^27/10

a = 27/10

B) We simply negate what we have above in terms of the index according to the indices law below;

a^b = 1/a^-b

Hence, we have that;

1/x^-27/10

3 0
3 years ago
What is the expanded equivalent of sin(a + b)
laila [671]
Sin(a + b) = sin a .cos b + cos a . sin b
5 0
3 years ago
Read 2 more answers
A new carpet cleaning company claims that they can clean 3 times as many carpets in 1 week as another company. If both companies
inna [77]

Answer:

The number of carpets cleaned by new company per week  is 249

Step-by-step explanation:

Let us assume :

The number of carpets cleaned by old company in 1 week = m

So, the number of carpets cleaned by new company in 1 week

= 3 x ( Number of carpets cleaned by old company)

 = 3 (m) = 3 m

Total carpet cleaned altogether in a week  = 332

So, Total Carpets cleaned by both companies in 1 week

= Number of carpets cleaned by ( Old + New) company in 1 week.

=  m + 3  m =  4 m

⇒  4  m = 332

or, m = 332 / 4 = 83  , or m = 83

Hence number of carpets cleaned by old company per week = m = 83

The number of carpets cleaned by new company per week

= 3 m =  3 x 83= 249

8 0
4 years ago
Pratap Puri rowed 14 miles down a river in 2 ​hours, but the return trip took him 3 and one half hours. Find the rate Pratap can
SOVA2 [1]

speed of current is 1.5 mi/hr

Answer:

let the rate in still water be x and rate of the current be y.

speed down the river is:

speed=distance/time

speed=14/2=7 mi/h

speed up the river is:

speed=(14)/(3.5)=4 mi/hr

thus total speed downstream and upstream will be:

x+y=7...i

x-y=4.......ii

adding the above equations i and ii we get:

2x=11

x=5.5 mi/hr

thus

y=5-5.5=1.5 mi/r

thus the speed in still waters is 5.5 mi/hr

speed of current is 1.5 mi/hr

7 0
2 years ago
Need the answers for 4-8
Fed [463]

Answer:

hope this helps you out ask me if you need more help

6 0
3 years ago
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