Answer:
The exponential Function is .
Farmer will have 200 sheep after <u>15 years</u>.
Step-by-step explanation:
Given:
Number of sheep bought = 20
Annual Rate of increase in sheep = 60%
We need to find that after how many years the farmer will have 200 sheep.
Let the number of years be 'h'
First we will find the Number of sheep increase in 1 year.
Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.
framing in equation form we get;
Number of sheep increase in 1 year =
Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years is equal to 200.
Framing in equation form we get;
The exponential Function is .
Subtracting both side by 20 using subtraction property we get;
Now Dividing both side by 12 using Division property we get;
Hence Farmer will have 200 sheep after <u>15 years</u>.
answer- 18
explanation- 40% of 120= 48 and 25% of 120= 30.
hope this helps !
Answer:
-25/12
Step-by-step explanation:
first, you need a common denominator. in this case, it's 12.
-1/3=-4/12
-7/4=-21/12
and then you add
-4+-21=-25
so -25/12 is your answer
Answer:
its 19. 60 just add it three more times and that is your answer
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90
2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10
Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b
2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10
3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100
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Answer: The numbers are 100 and 10</span>