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3 years ago

I really need help please and thank you

Mathematics

2 answers:

loris [4]3 years ago

7 0

Answer:

15 and 20

Step-by-step explanation:

HACTEHA [7]3 years ago

6 0

Answer:

13 is answer

5=y-8

5+8=y

y=13

5<13-8

5<5

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How do you write 18 tens in standard form

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If Anna walled for 5 miles and then turned around and went back what is her displacement?

damaskus [11]

If she went back 5 miles than the displacement would be 0.

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3 years ago

The boxplot displays the scores from an economics chapter test. identify the second quartile.

netineya [11]

Answer:

Step-by-step explanation:

The middle line is the median, then from left to right the lines are the first, second, third and fourth quartile.

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3 years ago

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Fred and Ted are interested in the average height of NC State students. They randomly sample students from NC State and construc

Nataly [62]

Answer:

a. Fred's margin of error is larger than Ted's.

Step-by-step explanation:

Margin of error of a confidence interval:

$M = z\frac{\sigma}{\sqrt{n}}$

In which z is related to the confidence level(the higher the confidence level the larger the value of z) $\sigma$ is the standard deviation of the population and n is the size of the sample.

From this, we have that:

A higher confidence level leads to a larger margin of error.

A larger sample size leads to a smaller margin of error.

In this question:

Same confidence level.

Fred's sample is smaller, so his margin of error will be larger.

The correct answer is given by option a.

8 0

3 years ago

A water balloon is 5 feet above the ground when Sally launches it into the air. Use the quadratic equation 0 = -t^2 + 4t + 5 to

rodikova [14]

Answer:

$t=5\ sec$

Step-by-step explanation:

we have

$-t^{2} +4t+5=0$

Solve the quadratic equation to find the zero's or x-intercepts

Remember that

The x-intercepts are the values of x when the value of y is equal to zero ( water balloon reach the ground)

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-t^{2} +4t+5=0$

$a=-1\\b=4\\c=5$

substitute in the formula

$t=\frac{-4(+/-)\sqrt{4^{2}-4(-1)(5)}} {2(-1)}$

$t=\frac{-4(+/-)\sqrt{36}} {-2}$

$t=\frac{-4(+/-)6} {-2}$

$t=\frac{-4(+)6} {-2}=-1$

$t=\frac{-4(-)6} {-2}=5$

therefore

the solution is $t=5\ sec$

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3 years ago

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