Remember your kinematic equations for constant acceleration. One of the equations is
![x_{f} = x_{i} + v_{i}(t) + \frac{1}{2} at^{2}](https://tex.z-dn.net/?f=%20x_%7Bf%7D%20%3D%20%20x_%7Bi%7D%20%2B%20%20v_%7Bi%7D%28t%29%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E%7B2%7D%20)
, where
![x_{f}](https://tex.z-dn.net/?f=x_%7Bf%7D%20)
= final position,
![x_{i}](https://tex.z-dn.net/?f=x_%7Bi%7D%20)
= initial position,
![v_{i}](https://tex.z-dn.net/?f=v_%7Bi%7D)
= initial velocity, t = time, and a = acceleration.
Your initial position is where you initially were before you braked. That means
![x_{i}](https://tex.z-dn.net/?f=x_%7Bi%7D%20)
= 100m. You final position is where you ended up after t seconds passed, so
![x_{f}](https://tex.z-dn.net/?f=x_%7Bf%7D%20)
= 350m. The time it took you to go from 100m to 350m was t = 8.3s. You initial velocity at the initial position before you braked was
![v_{i}](https://tex.z-dn.net/?f=v_%7Bi%7D)
= 60.0 m/s. Knowing these values, plug them into the equation and solve for a, your acceleration:
Your acceleration is approximately
.
Answer:
2. mechanical weathering can produce smaller pieces of rock that have more surface area for chemical weathering to work Explanation:
Mechanical weathering involves activities of living organisms or some geological processes. The bigger rocks are usually reduced to smaller rocks and further reduction might be limited or not posibble mechanically. This reduced rocks now increases the surface area available for chemical weathering; which further reduces the sizes of the rocks below the size range of mechanical weathering. one will recall that the rate of chemical reaction increases with exposed surface area.
Answer:
<em> -11,813.87N </em>
Explanation:
According to coulombs law, the Force between the two charges is expressed as;
F = kq1q2/d²
k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².
q1 = -0.00067 C
q2 = 0.00096 C
d = 0.7m
Substitute into the formula:
F = 9*10^9 * -0.00067 * 0.00096/0.7²
F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49
F = -578.88*10⁹⁻⁸/0.49
F = -578.88*10/0.49
F = -5788.8/0.49
F = -11,813.87N
<em>Hence the force between the two charges is -11,813.87N </em>
Answer:
![\theta = 0.195^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%200.195%5E0)
Explanation:
wavelength ![\lambda = 648 nm \ = 648*10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20648%20nm%20%5C%20%20%20%3D%20648%2A10%5E%7B-9%7Dm)
d = 0.190 mm = 0.190 × 10⁻³ m
D = 1.91 m
By using the formula:
![dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})](https://tex.z-dn.net/?f=dsin%20%5Ctheta%20%3D%20n%20%5Clambda%5C%5C%5C%5C%5Ctheta%20%3D%20sin%5E%7B%28-1%29%7D%28%5Cfrac%7Bn%20%5Clambda%7D%7Bd%7D%29%5C%5C%5C%5C%5C%5C%5Ctheta%20%3D%20sin%5E%7B%28-1%29%7D%28%5Cfrac%7B1%2A648%2A10%5E%7B-9%7D%7D%7B0.190%2A10%5E%7B-3%7D%7D%29)
![\theta = 0.195^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%200.195%5E0)
The first maximum will appear at an angle
from the beam axis
The last picture represents a pure compound