Answer:
The distance of the first bright fringe is given as 
The distance of the second dark fringe from the central bright fringe is given as 
Explanation:
From the question we are told that
The slit separation distance is 
The distance of the slit from the screen is 
The wavelength is 
For constructive interference to occur the distance between the two slit is mathematically represented as

Where m is the order of the fringe which has a value of 1 for first bright fringe
Substituting values


For destructive interference to occur the distance between the two slit is mathematically represented as
![Y_D = [n + \frac{1}{2} ] \frac{\lambda D}{d}](https://tex.z-dn.net/?f=Y_D%20%20%3D%20%20%5Bn%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%20%5Cfrac%7B%5Clambda%20D%7D%7Bd%7D)
m = 2
so the formula to get the dark fringe is 
Now substituting values
![Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}](https://tex.z-dn.net/?f=Y_D%20%3D%20%5B%201%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%20%2A%20%5Cfrac%7B633%20%2A10%5E%7B-9%7D%20%2A%203.23%20%7D%7B0.00115%7D)


Average Velocity= displacement/time Av=50/0.50 Av=100
Answer:


Explanation:
Average power for the human sprinter is given as

so we have



Average power for greyhound is given as



Answer:
Explanation:
Given that,
Weight of jet
W = 2.25 × 10^6 N
It is at rest on the run way.
Two rear wheels are 16m behind the front wheel
Center of gravity of plane 10.6m behind the front wheel
A. Normal force entered on the ground by front wheel.
Taking moment about the the about the real wheel.
Check attachment for better understanding
So,
Clock wise moment = anti-clockwise moment
W × 5.4 = N × 16
2.25 × 10^6 × 5.4 = 16•N
N = 2.25 × 10^6 × 5.4 / 16
N = 7.594 × 10^5 N
B. Normal force on each of the rear two wheels.
Using the second principle of equilibrium body.
Let the rear wheel normal be Nr and note, the are two real wheels, then, there will be two normal forces
ΣFy = 0
Nr + Nr + N — W = 0
2•Nr = W—N
2•Nr = 2.25 × 10^6 — 7.594 × 10^5
2•Nr = 1.491 × 10^6
Nr = 1.491 × 10^6 / 2
Nr = 7.453 × 10^5 N
Answer:
El avión recorrió 45 km en los 180 s.
Explanation:
La relación entre velocidad, distancia y tiempo se da de la siguiente manera;

Por lo cual los parámetros dados son los siguientes;
Velocidad = 900 km/h = 250 m / s
Tiempo = 180 s
Estamos obligados a calcular la distancia recorrida
De la ecuación para la velocidad dada arriba, tenemos;
Distancia recorrida = Velocidad pf viaje × Tiempo de viaje
Distancia recorrida = 900 km/h × 180 s = 900
Distancia recorrida = 900 km/h × 1 h/60 min × 1 min/60 s × 180 s = 45 km
Por lo tanto, el avión viajó 45 km en 180 s.