Answer:
v₀₂ = -2.67 m / s
Explanation:
Let's use the conservation of the moment, for this we define a system formed by the two cars.
Consider the north direction as positive and the subscript 1 will be used for car 1 and the subscript 2 for the second car
Initial instant. Before the crash
p₀ = -m₁ v₀₁ + m₂ v₀₂
Final moment. Right after the crash
p_f = (m₁ + m₂) v
p₀ = p_f
-m₁ 
+ m₂ v_{o2} = (m₁ + m2) v_{f}
v₀₂ = 
+ 
let's calculate
v₀₂ = 
v₀₂ = -2.67 m / s
the negative sign indicates that the carriage moves in the opposite direction of the temperies
Beta particle cannot penetrate theory for into the solid because they have lower velocity
Acceleration in a velocity vs time graph is just the slope at that point. The reason for that is because the definition of acceleration is the change in velocity per unit of time. In this case we want instantaneous, which is the derivative or tangent line at that point.
At 3s we can see the slope is 0, so that means his acceleration is zero. That means he was moving at a constant velocity
At 5s we can see that the slope is negative. And from 5s to 6s the change in velocity is -5m/s^2
At 7s we can see the slope is very positive. And from 7s to 8s the change in velocity is +15m/s^2
And again, at 9s the slope is 0 so his acceleration is also zero. He’s moving at a constant velocity
If you take the integral of a velocity vs time graph, you get position. So the area underneath a velocity vs time graph is the distance traveled. Anything below the x axis is considered negative distance. We need to take the area of a triangle and the area of two rectangles to find the distance.
So, let’s do the two rectangles first. From 8s to 9s it is a width of 1 and a length of 40. So the area would be 40 meters. Let’s do the second rectangle. From 7s to 8s it is a width of 1. Then the length goes up to 25. So the area is 25 meters.
Now the triangle, the base is 1 and the height is 15. Divide 15 in half to get 7.5 meters
25 + 40 + 7.5 = 72.5 meters
The force that a moving object exerts on another object upon colliding with it is rather the change in momentum divided by the amount of time elapsed during the collision.
F = Δp/Δt
F = force, Δp = change in momentum, Δt = elapsed time
Usually we say momentum is proportional to mass instead of saying momentum is proportional to weight. But sure, for two objects on the same planet, greater weight implies greater mass. Momentum is the product of mass and velocity:
p = mv
p = momentum, m = mass, v = velocity
So we have two identical cars on the same planet with one car traveling 30mph faster than the other. Let's say they both collide with a tree, both coming to a rest, and the collisions take the same amount of time to happen. The faster car loses a greater amount of momentum over the same amount of time, therefore delivering a greater force.
Choice B
On a speed-versus-time graph, a straight line that slopes down toward
the right shows that the object is experiencing a constant deceleration.
