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sergejj [24]
2 years ago
12

The area of the base of a cylindrical container is defined by b(x) = x*2 - x + 12. Find

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
4 0

Answer: V=x^3-2x^2+13x-12

Step-by-step explanation:

Given

The area of the base is given by b(x)=x^2-x+12

The height of the container is h(x)=x-1

The volume of the cylindrical container is

V=Area\times height

Insert the values

\Rightarrow V=\left( x^2-x+12\right)\cdot \left(x-1\right)\\\Rightarrow V=x^3-x^2+12x-x^2+x-12\\\Rightarrow V=x^3-2x^2+13x-12

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Second option, scale factor is 2.5

Step-by-step explanation:

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3 years ago
General term for -13, -11, -9, -7
timurjin [86]

The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

<h3>Arithmetic progression</h3>

-13, -11, -9, -7

  • First term, a = -13
  • Second term = -11

Common difference, d = Second term - first term

= -11 - (-13)

= -11 + 13

= 2

Therefore,

Tn = a + (n - 1)d

Where,

  • n = number of terms

Tn = a + (n - 1)d

= -13 + (n - 1)2

= -13 - 2n - 2

Tn = -15 - 2n

So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

Learn more about arithmetic progression:

brainly.com/question/6561461

#SPJ1

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