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Anton [14]
3 years ago
3

Graph the equation by plotting three points if all three are correct the line will appear -3x=2x-7 ?? Can some one please help ?

??
Mathematics
1 answer:
katrin [286]3 years ago
6 0
In this problem, we assume that the function is in typo since there are no y variables present in the equation- that is the equation becomes <span>-3x=2y-7. In this case, we can find three points lying in the line by assuming x as any number for example from 1 to 3 and then substituting these values separately and getting y correspondingly. </span>
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Divide 3/16 by 5/2<br> EXPLAIN ANSWER PLZ! AND FAST! I WILL NAME YOU BRANLIEST!
Travka [436]

Use the KCF method to divide

3/6  /  5/2 =  3/6 x 2/5, which equals 1/5

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1.64 divide by 22 I don’t even know this help me?
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The answer would be 7.54
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A roller coaster starts from a deck at an elevation of 20 feet above the ground. On the first hill it climbs 83 feet and then dr
Fantom [35]
Initially started 20 feet from the ground .
Went uphill 83 feet.
So: 20 + 83 = 103. The coaster is 103 ft above at this point.

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Sam had monkeys and lions in his zoo, He counted legs one day to discover that he could see 76 feet on the ground. He knew that
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3 years ago
Ejercicio 3. Aplica las leyes de los exponentes de potencia elevada a otra potencia y de producto,
OLga [1]

Los resultados son los siguientes:

  1. 2097152
  2. \frac{1}{729}
  3. b^{12}
  4. x^{24}
  5. x^{\frac{6}{5} }
  6. 3600
  7. a^{6}\cdot b^{10}\cdot c^{-8}
  8. 200\cdot x^{19}
  9. 108\cdot y^{6}

En este ejercicio debemos aplicar cualesquiera de las siguientes propiedades asociadas a los exponentes:

(i) (a^{b})^{c} = a^{b\cdot c}

(ii) a^{c}\cdot b^{c} = (a\cdot b)^{c}

(iii) a^{-b} = \frac{1}{a^{b}}

(iv) a^{b} = a^{b}, donde a es negativo o positivo y b es par.

(v) (-a)^{b} = -a^{b}, donde a es positivo y b es impar.

(vi) a^{b}\cdot a^{c} = a^{b+c}

A continuación, tenemos los siguientes resultados:

a) (2^{3})^{7} = 8^{7} = 2097152

b) (3^{3})^{-2} = 3^{-6} = \frac{1}{729}

c) (b^{3})^{4}=b^{12}

d) [(x^{2})^{3}]^{4} = (x^{6})^{4} = x^{24}

e) \left(x^{\frac{3}{5} }\right)^{2} = x^{\frac{6}{5} }

f) (3\cdot 4\cdot 2)^{5} = 3^{2}\cdot 4^{2}\cdot 5^{2} = 9\cdot 16\cdot 25 = 3600

g) (a^{3}\cdot b^{5}\cdot c^{-4})^{2} = (a^{3})^{2}\cdot (b^{5})^{2}\cdot (c^{-4})^{2} = a^{6}\cdot b^{10}\cdot c^{-8}

h) (2\cdot x^{5})^{3}\cdot (-5\cdot x^{2})^{2} = (2^{3}\cdot x^{15})\cdot [(-5)^{2}\cdot x^{4}] = (8\cdot x^{15})\cdot (25\cdot x^{4}) = (8\cdot 25)\cdot x^{19} = 200\cdot x^{19}

i) \left(3\cdot y^{\frac{2}{3} }\right)^{3}\cdot (2\cdot y^{2})^{2} = (27\cdot y^{2})\cdot (4\cdot y^{4}) = 108\cdot y^{6}

Invitamos cordialmente a consultar esta pregunta sobre potencias: brainly.com/question/24239709

8 0
3 years ago
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