Ca= 2 ve
Be=2 ve
Mg=2 ve because they are in Group 2a.
They are slightly less reactive than Group 1a, but more dense that Group 1a.
Answer: 1 mol of will be produced from this reaction.
Explanation: Reaction follows,
As seen from the balanced chemical equation above, we get
For every 3 moles of Aluminium and 3 moles of , 1 mole of is formed.
For every 3 moles of Aluminium and 3 moles of , 1 mole of is formed.
For every 3 moles of Aluminium and 3 moles of , 3 moles of is formed.
For every 3 moles of Aluminium and 3 moles of , 6 moles of is formed.
Letter C would be the correct answer
First, convert the amount of KNO3 to moles using the molar mass:
58.6 g / 101.11 g/mol = 0.5796 mol KNO3
Next, using the given balanced reaction, use the stoichoimetric ratio to calculate the number of mole of oxygen that will be produced. From the reaction, for every 4 moles of KNO3 that decomposes, there are 5 moles of O2 formed. So,
0.5796 mol KNO3 x (5/4) = 0.7254 moles O2
Therefore, when 58.6 g of KNO3 decomposes, there are 0.7254 moles of O2 that will be formed.