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Sonja [21]
3 years ago
13

If x= -2, y = 4, find the value of 2x2 - 3xy + 5​

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0

Answer:

I am assuming when you say 2x2 you mean 2x squared so using that, your answer should be -35 if Im correct.

Step-by-step explanation:

Brainliest?!?

Galina-37 [17]3 years ago
5 0

Answer:

21

Step-by-step explanation:

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(Score for Question 3: ___ of 5 points)
mote1985 [20]
Here are the step for solving this:
1. 3y + 5 > 23
-5 -5
3y/3 > 18/3
y > 6

In words what you are doing is getting y by itself on one side. Subtract the 5 to undo the adding of 5 first. Then, divide both sides by 3.


7 0
3 years ago
How many quarts are there in 10 ½ gallons
aksik [14]

Answer:

42 quarts

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
X squared -8x+14=2x-7
Stella [2.4K]

Answer:

x = 3 or x = 7

Step-by-step explanation:

X² - 8x + 14 = 2x - 7

x² - 8x + 14 - 2x + 7 = 0

Now we have a quadratic equation ;

x² - 10x + 21 = 0

-3 and - 7 gives a sum of - 10 and a product of 21

x² - 3x - 7x + 21 = 0

x(x - 3) - 7(x - 3) = 0

(x - 3) = 0 or (x - 7) = 0

x = 3 or x = 7

5 0
3 years ago
What number is 6% of 30?
rosijanka [135]

so you would do 6/100 *30/1 wich is 90/50 as a pecent is 180 an move the decimal place 2 times

<u>ANSWER</u> 1.8


3 0
3 years ago
Read 2 more answers
Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance
kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

C^{2}=A^{2}+B^{2}-2ABcos \gamma

so we can solve the formula for C so we get:

C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}

and now we can substitute the values we know:

C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}

C=\sqrt{16+64-32\sqrt{2}}

C=\sqrt{80-32\sqrt{2}} mph

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0
3 years ago
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