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3 years ago

What does y= 3x - 2 equal?

Mathematics

2 answers:

cestrela7 [59]3 years ago

8 0

THE ANSWER WOULD BE X=2/3

guapka [62]3 years ago

8 0

Answer:

i think 3x - y = 2 but i am not really sure tho but if i am, i am so sorry if i am not right have a good one hope u the best on it good luck :)

Step-by-step explanation:

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To begin a bacteria study, a petri dish had 2800 bacteria cells. Each hour since, the number of cells has increased by 7.2%. Let

Rudiy27

The function that models exponential growth is:

P(t) = P0*(1 + r)^t, where

P0 = P(0) is the initial value of P

r is the growth rate as a decimal

In our case we have:

P(0) = 2800

r = 0.035 or 3.5%

P(t) = 2800*(1 + 0.035)^t

P(t) = 2800*(1.035)^t

The same exponential function written using y and t is:

y = 2800*1.035^t.

Explanation: https://softmath.com/algebra-word-problems/to-begin-a-bacteria-study-a-petri-dish-had-2800-bacteria

7 0

2 years ago

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

I have a lot of questions to ask on mathematics...<br>so pls help so fast<br>thnx a lot...

melomori [17]

Answer:

WHAT DO YOU need help with

8 0

3 years ago

(x1/2y)^4 help me please I need an A

vodka [1.7K]

Answer:

this is simplify 1/16 x4 y4

4 0

3 years ago

Carlos drove to the train station and back. The trip there took five hours and the trip back took four hours. What was Carlos' a

katrin2010 [14]

Answer: 54.4 mph

Step-by-step explanation:

First find the distance to the train station. If it took Carlos 4 hours to come back driving at 68 mph, the distance is:

= Speed * time

= 68 * 4

= 272 miles

This means that Carlos drove for 5 hours to cover 272 miles the first time. His average speed was therefore:

= Distance / time

= 272/5

= 54.4 mph

3 0

2 years ago

What does y= 3x - 2 equal?​

What does y= 3x - 2 equal?