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spayn [35]
2 years ago
11

???????????????????????????

Mathematics
1 answer:
FinnZ [79.3K]2 years ago
7 0

Answer:

y-(-20)=1(x-(-10))

Step-by-step explanation:

If you're really in college you should know this, but here's the explanation:

m= <u>-9-(-20)</u>

      1-(-10)

  = <u>11</u>

     11

m = 1

The equation is y-y^1=m(x-x^1)

Replace the y^1, m, and x^1 from the first point

You get y-(-20)=1(x-(-10))

Or simplify that into y+20=x+10

You can also simplify it more but I don't think you need that for that question

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Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?
Vaselesa [24]
ANSWER

f( - 6) =  10


EXPLANATION

The given function is
f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40

According to the remainder theorem,

f( - 6) = R
where R is the remainder when
f(x)

is divided by
x + 6


We therefore substitute the value of x and evaluate to obtain,

f( - 6) =  { (- 6)}^{4}  + 8 {( - 6)}^{3}  + 10 { (- 6)}^{2}  - 7( - 6)+ 40




f( - 6) =  1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40




f( - 6) =  1296  - 1728 + 360  + 42+ 40



This will evaluate to,


f( - 6) =  10


Hence the value of the function when
x =  - 6

is
10



According to the remainder theorem,
10
is the remainder when

f(x) =  {x}^{4}  + 8 {x}^{3}  + 10 {x}^{2}  - 7x + 40
is divided by
x + 6
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