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morpeh [17]
3 years ago
14

Given f (x) = 1/5 (6 – x)^2 what is the value of f(16)?​

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
3 0
F(16)=1/5(6-16)^2
f(16)=1/5(-10)^2
f(16)=1/5(100)
f(16)=20
Monica [59]3 years ago
3 0

Answer:

20

Step-by-step explanation:

if f(x)=1/5(6-x)^2 when f(16)you will replace x by 16 then solve it like this

f(16)=1/5(6-16)^2

= 1/5(-10)^2

=1/5(100)

=20

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