Given f (x) = 1/5 (6 – x)^2 what is the value of f(16)?
2 answers:
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Answer:
B
Step-by-step explanation:
let f(x) = y and rearrange making x the subject
y = ( multiply both sides by 7 to clear the fraction )
7y = x + 2 ( subtract 2 from both sides )
7y - 2 = x
Change y back into terms of x with x the inverse function, that is
p(x) = 7x - 2