Given f (x) = 1/5 (6 – x)^2 what is the value of f(16)?
2 answers:
F(16)=1/5(6-16)^2
f(16)=1/5(-10)^2
f(16)=1/5(100)
f(16)=20
Answer:
20
Step-by-step explanation:
if f(x)=1/5(6-x)^2 when f(16)you will replace x by 16 then solve it like this
f(16)=1/5(6-16)^2
= 1/5(-10)^2
=1/5(100)
=20
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