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3 years ago

Given f (x) = 1/5 (6 – x)^2 what is the value of f(16)?

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

3 0

F(16)=1/5(6-16)^2
f(16)=1/5(-10)^2
f(16)=1/5(100)
f(16)=20

Monica [59]3 years ago

3 0

Answer:

Step-by-step explanation:

if f(x)=1/5(6-x)^2 when f(16)you will replace x by 16 then solve it like this

f(16)=1/5(6-16)^2

= 1/5(-10)^2

=1/5(100)

=20

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