<h3><u>Solution</u></h3>
<u>Given </u><u>:</u><u>-</u>
- Perimeter of rectangle = 72 cm
- The length is 3 more than twice the width.
<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>
<h3 /><h3>
<u>Explantion</u></h3>
<u>Using </u><u>Formula</u>
<u>Let,</u>
- Length of Rectangle = x cm
- Breadth of Rectangle = y cm
<u>According</u><u> to</u><u> question</u><u>,</u>
==> perimeter of Rectangle = 72
==> 2(x+y) = 72
==> x + y = 72/2
==> x + y = 36_________________(1)
<u>Again,</u>
==> x = 2y + 3
==> x - 2y = 3__________________(2)
<u>Subtract</u><u> </u><u>equ(</u><u>1</u><u>)</u><u> </u><u>&</u><u> </u><u>equ(</u><u>2</u><u>)</u>
==> y + 2y = 36 - 3
==> 3y = 33
==> y = 33/3
==> y = 11
<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>
==> x - 2×11 = 3
==> x = 3 + 22
==> x = 25
<h3><u>Hence</u></h3>
- <u>Length</u><u> of</u><u> </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u> </u><u>cm</u>
- <u>Width </u><u>of </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u> </u><u>cm</u>
<h3>
<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h3>
<h3 />
-3x+6.3=-14.4
-6.3=-6.3
-<u>3x</u>=-<u>20.7</u>
-3 -3
x=6.9
The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.
What is a Dominant Trait?
A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.
Given the following traits:
A - attached earlobes (dominant allele)
a - unattached earlobes (recessive allele)
A cross between Aa and aa is shown in the image attached below.
The offspring having attached earlobes = 2 Aa = 50%.
50% of the osspring will have attached earlobes.
Learn more about dominant trait on:
brainly.com/question/16616523
Answer:
It is a function
Step-by-step explanation:
The x-values do not repeat so it is a function.
Answer:
(2x - 3) • (x + 4)
Step-by-step explanation:
Step 1 :
Equation at step 1 :
(2x2 + 5x) - 12
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 2x2+5x-12
The first term is, 2x2 its coefficient is 2 .
The middle term is, +5x its coefficient is 5 .
The last term, "the constant", is -12
Step-1 : Multiply the coefficient of the first term by the constant 2 • -12 = -24
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is 5 .
-24 + 1 = -23
-12 + 2 = -10
-8 + 3 = -5
-6 + 4 = -2
-4 + 6 = 2
-3 + 8 = 5
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 8
2x2 - 3x + 8x - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-3)
Add up the last 2 terms, pulling out common factors :
4 • (2x-3)
Step-5 : Add up the four terms of step 4 :
(x+4) • (2x-3)
Which is the desired factorization