3 x 1/8 bottom left. The third one
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
Answer: Ksh 6144
Step-by-step explanation:
On Thursday, a fruit vendor bought 1948 oranges on a Thursday and sold 750. The number of oranges left will be: = 1948 - 750 = 1198
On n Friday, he sold 240 more oranges than on Thursday. This means the number of oranges sold is: = 240 + 750 = 990.
The number for f oranges left will then be: = 1198 - 990 = 208
On Saturday, he bought 560 more
oranges, the total oranges that the vendor has now will be:
= 208 + 560 = 768
Since sold all the oranges he had at a price of Ksh. 8 each, the amount if money made will be:
= Ksh 8 × 768
= Ksh 6144
The vendor made Ksh 6144
Answer:
infinite solutions
Step-by-step explanation:
Simplify 3x-x-53x−x−5 to 2x-52x−5.
2x-5=2(x+2)-92x−5=2(x+2)−9
2 Expand.
2x-5=2x+4-92x−5=2x+4−9
3 Simplify 2x+4-92x+4−9 to 2x-52x−5.
2x-5=2x-52x−5=2x−5
4 Since both sides equal, there are infinitely many solutions.
Infinitely Many Solutions
