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jolli1 [7]
3 years ago
10

Iodide (KI). Identify the correct products of this

Chemistry
2 answers:
kap26 [50]3 years ago
7 0

Answer:

AgI + KNO3

Explanation:

double replacement

TEA [102]3 years ago
4 0

Answer:

AgNO3 + KI → Agl + KNO3. Double-replacement reaction

Explanation:

Based on solubility rules, Silver, Ag produce an insoluble salt in presence of halides (Fluorides F-, Chlorides Cl-, Iodides, I-, and bromides Br-). That means the mixture of AgNO3 (Ag⁺ ions) with KI (I- ions) produce AgI as insoluble salt.

The reaction is:

<h3>AgNO3 + KI → Agl + KNO3</h3><h3 />

And this is a double-replacement reaction where the cations exchange of anion to produce 2 new compounds.

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A bottle with 18.02 grams of water contains
8_murik_8 [283]
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8 0
3 years ago
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What is the total pressure in units of kPa in a 7.85 L container that contains 4.45 moles of N2 and 2.45 moles of O2 at a temper
IgorC [24]

Answer:

Total pressure = 22.15 atm

Explanation:

Given data:

Total pressure = ?

Volume of container = 7.85 L

Number of moles of N₂ = 4.45 mol

Number of moles of O₂ = 2.45 mol

Temperature = 307 K

Solution:

Pressure of N₂:

PV = nRT

P = nRT/V

P = 4.45 mol ×0.0821 atm.L/mol.K ×307K / 7.85L

P = 112.16 atm.L/7.85 L

P = 14.28 atm

Pressure of O₂:

PV = nRT

P = nRT/V

P = 2.45 mol ×0.0821 atm.L/mol.K ×307K / 7.85L

P = 61.75 atm.L/7.85 L

P = 7.87 atm

Total pressure = P(N₂) + P(O₂)

Total pressure = P( 14.28 atm)  +  P( 7.87 atm)

Total pressure = 22.15 atm

6 0
3 years ago
What is the mass percent concentration of a solution containing 29.0 g NaCl and 115.0 mL of water? Assume a density of 1.00 g/mL
marin [14]

Answer:

Mass percent concentration: 25,2% m/m

Explanation:

The percentage mass by mass indicates the grams of solute in 100 grams of solution. We convert the ml of water into g from the density formula:

δ= m/v    m=δx v= 1 g/ml x 115 ml= 115 g

115g solution-----29 g NaCl

100g solution----x=(100g solutionx29 g NaCl)/115g solution

x=25,2173913 g NaCl

5 0
3 years ago
A buffer is prepared by dissolving 0.80 moles of NH3 and 0.80 moles of NH4Cl in 1.00 L of aqueous solution. If 0.10 mol of NaOH
Vikki [24]

Answer:

a. 10.54

Explanation:

reaction is

NH₃ +  NaOH   -----------------NH₄Cl + H₂O

0.10 mol NaOH will consume 0.10 mol NH₃ thereby decreasing the initial amount of moles NH₃ and increasing that of NH₄Cl

mol NH₃  = 0.80 - 010 = .70

mol NH₄Cl = 0.80 + .10 = 0.90

pH = pKₐ + log (( NH₃/NH₄Cl))

pH =  9.26 + log (( 0.90 + 0.70)) = 9.26 + 0.11 = 10.54

7 0
3 years ago
If calcium were to react with carbon, what would likely form?
Lady_Fox [76]

Answer: calcium oxide will react with carbon dioxide to form calcium carbonate. I don't know if that's what you were asking.

Explanation:

6 0
3 years ago
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