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docker41 [41]
3 years ago
13

If calcium were to react with carbon, what would likely form?

Chemistry
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer: calcium oxide will react with carbon dioxide to form calcium carbonate. I don't know if that's what you were asking.

Explanation:

You might be interested in
Convert each of the measurements given to the new unit stated using the factor label method (dimensional analysis). Show all wor
KengaRu [80]
For cm to m, you need to divide by 100 to get m:
26cm/100= 0.26m

For hr to min, you need to multiply by 60 to get min:
4hr x 60= 240min

For km to m, you need to multiply by 1000 to get m:
3.25km x 1000= 3250m

For ft to in, you need to multiply by 12 to get in:
5ft x 12=60in

So we have:
0.26m
240min
3250m
60in


6 0
3 years ago
Plz help plz help plz help meed
Leviafan [203]

Answer:

5106.38 Ω

Explanation:

From the question given above, the following data were obtained:

Current (I) = 0.0235 A

Voltage (V) = 120 V

Resistor (R) =?

From ohm's law,

V = IR

Where:

V => is the voltage.

I => is the current

R => is the resistor

With the above formula, we can obtain the size of the resistor needed as follow:

Current (I) = 0.0235 A

Voltage (V) = 120 V

Resistor (R) =?

V = IR

120 = 0.0235 × R

Divide both side by 0.0235

R = 120 / 0.0235

R = 5106.38 Ω

Thus, the size of the resistor needed is 5106.38 Ω

3 0
3 years ago
If this compounds (N2O) molecular mass is 88g are the empirical and molecular formulas the same as one another or different
Softa [21]

Answer:

No

Explanation:

Let us examine this problem carefully:

Given compound is N₂O

Molecular mass = 88g

Now,

The empirical formula is the simplest formula of a compound.

The molecular formula is the true formula of the compound that shows that actual ratios of the atoms in a compound.

To find if they both have the same molecular and empirical formula, they must have the same molecular mass.

 For N₂O;

     Molecular mass = 2(14) + 16 = 44g/mole

But the true and given molecular formula of the compound is 88g/mole

This shows that the compound given is the empirical formula of the compound.

  Molecular formula:

              molecular mass of empirical formula x n = molecular mass of molecular formula

         n  = \frac{88}{44}  = 2

Molecular formula of compound = 2(N₂O) = N₄O₂

Therefore the empirical and molecular formulas are not the same

8 0
4 years ago
How many moles are present in 454 grams of co2?
babunello [35]
Moles=mass/Mr 
mass=454
Mr=12+16+16=44
So,454/44=10.31mol
Answer is:10.31mol
3 0
3 years ago
Read 2 more answers
The rate of reaction is fastest at the _______ of a chemical reaction
astraxan [27]

Answer:

Beginning or Start

Explanation:

Reactions can be followed by measuring changes in concentration, mass and volume of reactants or products. The rate is highest at the start of the reaction because the concentration of reactants is highest at this point.

Hope this helped! :^)

5 0
3 years ago
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