6. A 0.1310 g sample of an unknown diprotic acid is diluted to 100.00 mL and titrated by using 0.1910 M NaOH. If 14.20 mL of the
1 answer:
Answer:
Explanation:
Hello,
In this case, it is more convenient to define this titration in terms of normality:
In such a way, the normality of the acid, considering the normality of sodium hydroxide equals its molarity (one hydroxile in its structure) is:
Thus, the moles are:
Hence, the molar mass:
Best regards.
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Answer:
Here's what I get
Explanation:
1. Sugar
(a) Dissolving in water
The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.
(b) Addition of sodium hydroxide
Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.
2. Magnesium sulfate
(a) Dissolving in water
The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.
(b) Addition of sodium hydroxide
Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.
