Yayyyy I’m so happy you got good grades
Answer:
Suppose N is the size of a population of radioactive atoms at a given time t, and dN is the amount by which the population decreases in time dt; then the rate of change is given by the equation dN/dt = −λN, where λ is the decay constant.
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Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.
For this, a sample of 276 healthy men and women was taken.
n₁= 96 had few social outlets
n₂= 105 had six or more activities
These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:
p'₁= 0.62 (62% of the people with few social outlets got sick)
p'₂= 0.35 (35% of the people with six or more activities got sick)
The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.
You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂
(p'₁ - p'₂) ± 

(0.62-0.35) ± 2.586 
[0.094; 0.045]
With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.
I hope it helps!
if not correct me c:
Step-by-step explanation:
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