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Lelu [443]
3 years ago
6

PLS HELP I WILL GUVE POINT

Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:

D

Step-by-step explanation:

-3*7=-21k+2

inysia [295]3 years ago
8 0

Answer:

what thye said loll

Step-by-step explanation:

You might be interested in
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

__

The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

__

The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
2 years ago
(2,-4) and (6,2).<br> Find the mid point
Olin [163]

Answer:

The answer is

<h2>( 4 , - 1)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(2,-4) and (6,2)

The midpoint is

M = ( \frac{2 + 6}{ 2}  , \:  \frac{ - 4 + 2}{2} ) \\  = ( \frac{8}{2}  \: , \:  -  \frac{2}{2} )

We have the final answer as

<h3>( 4 , - 1)</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
What is the probability if rolling an 8 with one regular die if you roll the die just once?
lidiya [134]

Answer:

the answer to the probability question should be zero because there isn't an eight on a normal die. if you were to only roll once you would never get 8

8 0
3 years ago
Ifyou are asked to solve a system ofequations in which there is no linear equation to start with, you can sometimes begin by iso
maw [93]
What you typped is correct
7 0
3 years ago
MARKIN BRAINIEST!!! GIVIN 30PTS!!!
Sedbober [7]

Answer:

  • (-16x² +10x -3) +(4x² -29x -2)
  • (2x² -11x -9) -(14x² +8x -4)
  • 2(x -1) -3(4x² +7x +1)

Step-by-step explanation:

I find it takes less work if I can eliminate obviously wrong answers. Toward that end, we can consider the constant terms only:

  1. -3 +(-2) = -5 . . . . possible equivalent
  2. -10 -5 = -15 . . . . NOT equivalent
  3. 3(-5) -2(5) = -25 . . . . NOT equivalent
  4. -9 -(-4) = -5 . . . . possible equivalent
  5. -7 -(-5) = -2 . . . . NOT equivalent
  6. 2(-1) -3(1) = -5 . . possible equivalent

Now, we can go back and check the other terms in the candidate expressions we have identified.

  1. (-16x² +10x -3) +(4x² -29x -2) = (-16+4)x² +(10-29)x -5 = -12x² -19x -5 . . . OK

  4. (2x² -11x -9) -(14x² +8x -4) = (2-14)x² +(-11-8)x -5 = -12x² -19x -5 . . . OK

  6. 2(x -1) -3(4x² +7x +1) = -12x² +(2 -3·7)x -5 = -12x² -19x -5 . . . OK

All three of the "possible equivalent" expressions we identified on the first pass are fully equivalent to the target expression. These are your answer choices.

7 0
3 years ago
Read 2 more answers
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