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Dahasolnce [82]
3 years ago
14

Can someone please explain how to go the answers for this

Mathematics
1 answer:
Effectus [21]3 years ago
7 0

Answer:

A=3, B=4, C=-5

Step-by-step explanation:

So A represents the amplitude, which is the distance between the midline (C), the middle of the graph, and the maximum (or minimum). B is the distance of the period of the graph. In this case, we see that the midline is C=-5 because that is the halfway point of the sine function. We also see that the period distance is B=5-1=4, so our period would be 2π/4 or π/2. Our amplitude would be A=3 because |a|=|-5-(-2)|=|-5+2|=|-3|=3. Observe the graph to see this visually.

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If the base of the parallelogram is 8 and the perimeter is 28 then what is the area?
LUCKY_DIMON [66]

Answer:

the answer is 28 for the area.

7 0
2 years ago
Find the equation of a line that passes through (-2,4) and (1,-2)
Basile [38]

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-2)}}}\implies \cfrac{-6}{1+2}\implies \cfrac{-6}{3}\implies -2

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}]\implies y-4=-2(x+2) \\\\\\ y-4=-2x-4\implies y = -2x

8 0
3 years ago
Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.
dusya [7]

\huge\color{black}\underline\mathbb{\:ANSWER}

\green{••••••••••••••••••••••••••••••••••••••••••••••••••}

Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.

x = −5

x = 6

<h2>x = −6</h2>

therefore the answer is

<h2>x = −6</h2>

\green{••••••••••••••••••••••••••••••••••••••••••••••••••}

\tt\color{black}{12:14AM}

\huge \tt{4/2/22}

(ノ^_^)ノ

4 0
2 years ago
Read 2 more answers
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
What is the answer to the equation?
s344n2d4d5 [400]
Y=-3x+5
the slope is negative because the line is going down from left to right
the y-intercept is 5 because that’s where the line crosses the y-axis
5 0
2 years ago
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