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White raven [17]
2 years ago
9

Q. Penelope is told to clean all the windows at her house. After cleaning 9 windows her job is

Mathematics
2 answers:
iVinArrow [24]2 years ago
7 0
30 windows in all. Look at the attachment for work.

algol [13]2 years ago
5 0

Answer:

30

Step-by-step explanation:

Proportions!

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Serjik [45]
12 x 6 x 3 =216. He can dress himself up in 216 different ways. 

I hope this helps!
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3 years ago
Refer to example 4. Predict how many out of 1,370 students have a television in their bedroom. (Glenco p. 795)
klio [65]

Answer:

990

Step-by-step explanation:

7 0
3 years ago
Need help ASAP really lost
svetoff [14.1K]
63 degrees, if that angle is 72 that means the other must be 54 (add to 180), and if that angle on the other triangle is 54, the others must be 63 (add to 180).
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3 years ago
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Translate this word phrase into a variable expression. 25 decreased by the sum of 6 and a number
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6x-25 six and a number(x) decreased by 25

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3 years ago
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A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz
marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean,\mu_xis calculated as:

\mu_x=\mu=204.9, \mu_x=sample \ mean

-The standard deviation,\sigma_x is calculated as:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean,\mu_x is calculated as:

\mu_x=\mu\\\\=75.9

#The sample standard deviation is calculated as follows:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

\mu_x=\mu=135.7

#Sample standard deviation:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0
3 years ago
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