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4 years ago

11

The story of space exploration began with unmanned exploration, moved into a period of manned exploration, and now appears

2 answers:

shusha [124]4 years ago

7 0

appears to be moving back toward unmanned exploration in the form of deep-space satellite exploration.

katovenus [111]4 years ago

6 0

Answer:

appears to be moving back toward unmanned exploration in the form of deep-space satellite exploration.

Explanation:

NASA moved from unmanned probing of space in its initial stage of space exploration to manned space exploration and moon landing and now has gone back to unmanned exploration into deeper space. Deep space is not completely known yet, and the exploration take year and are probably very dangerous for manned exploration for now.

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If an element has 2 valence electrons, how many dots will be in the elements dot diagram?

zaharov [31]

If we're talking about the amount of electron rings and the dots within the rings around an atom, the amount will be 1 ring, 2 dots.

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3 years ago

Determine the molarity of 4.67 moles of Li2SO3 dissolved to make 2.04 liters of solution

PSYCHO15rus [73]

You take the moles divided by the liters to get the molarity.

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3 years ago

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luda_lava [24]

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2 years ago

At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide:

gayaneshka [121]

<u>Answer:</u> The moles of bromine gas at equilibrium is 0.324 moles.

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .......(1)

Calculating the initial moles of hydrogen and bromine gas:

<u>For hydrogen gas:</u>

Moles of hydrogen gas = 0.682 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{0.682mol}{2.00L}=0.341M$

<u>For bromine gas:</u>

Moles of bromine gas = 0.440 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{0.440mol}{2.00L}=0.220M$

Now, calculating the molarity of hydrogen gas at equilibrium by using equation 1:

Equilibrium moles of hydrogen gas = 0.566 mol

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{0.566mol}{2.00L}=0.283M$

Change in concentration of hydrogen gas = 0.341 - 0.283 = 0.058 M

This change will be same for bromine gas.

Equilibrium concentration of bromine gas = $(\text{Initial concentration}-\text{Change in concentration})=0.220-0.058=0.162M$

Now, calculating the moles of bromine gas at equilibrium by using equation 1:

Molarity of bromine gas = 0.162 M

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$0.162M=\frac{\text{Moles of bromine gas}}{2.00L}\\\\\text{Moles of bromine gas}=(0.162mol/L\times 2.00L)=0.324mol$

Hence, the moles of bromine gas at equilibrium is 0.324 moles.

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3 years ago

26. For each of the following balanced equations, calculate how many grams of each product would be pro-

Dimas [21]

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