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atroni [7]
3 years ago
11

The story of space exploration began with unmanned exploration, moved into a period of manned exploration, and now appears

Chemistry
2 answers:
shusha [124]3 years ago
7 0

appears to be moving back toward unmanned exploration in the form of deep-space satellite exploration.

katovenus [111]3 years ago
6 0

Answer:

appears to be moving back toward unmanned exploration in the form of deep-space satellite exploration.

Explanation:

NASA moved from unmanned probing of space in its initial stage of space exploration to manned space exploration and moon landing and now has gone back to unmanned exploration into deeper space. Deep space is not completely known yet, and the exploration take year and are probably very dangerous for manned exploration for now.

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hat is the pressure of CO(g) in equilibrium with the CO2(g) and O2(g) in the atmosphere at 25 ????C? The partial pressure of O2(
Lubov Fominskaja [6]

Answer:

The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure

Explanation:

First, the balanced reaction is:

CO + 1/2O₂ → CO₂

The energies of formation are:

ΔG(CO)=-137.168kJ/mol

ΔG(O₂)=0

ΔG(CO₂)=-394.359kJ/mol

The energy of the reaction is:

delta-G_{reaction} =delta-G_{CO_{2} } -(delta-G_{CO} +1/2delta-G_{O_{2} } )\\delta-G_{reaction}=-394.359-(-137.168+0)=-257.191kJ/mol

The expression for calculate the partial pressure of CO is:

p_{CO} =\frac{p_{CO2} }{p_{O_{2} }^{1/2}*exp^{-\frac{delta-G}{RT} }   } \\p_{CO}=\frac{3x10^{-4} }{0.2^{1/2}*exp(-\frac{-257.191*1000}{8.314*298} ) } \\p_{CO}=5.54x10^{-49} atm

5 0
3 years ago
What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each quest
kenny6666 [7]

<u>Answer:</u> The daughter nuclide formed by the beta decay of given isotope is _{30}^{64}\textrm{Zn}

<u>Explanation:</u>

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

We are given:

Parent isotope = _{29}^{64}\textrm{Cu}

The chemical equation for the beta decay process of _{29}^{64}\textrm{Cu} follows:

_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta

Hence, the daughter nuclide formed by the beta decay of given isotope is _{30}^{64}\textrm{Zn}

4 0
3 years ago
What best describes the collision between ideal gas molecules
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An ideal gas is defined as one in which all collisions between atoms or molecules are perfectly eleastic and in which there are no intermolecular attractive forces. One can visualize it as a collection of perfectly hard spheres which collide but which otherwise do not interact with each other.

Happy to help
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Answer:

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