The story of space exploration began with unmanned exploration, moved into a period of manned exploration, and now appears

Chemistry

2 answers:

shusha [124]4 years ago

7 0

appears to be moving back toward unmanned exploration in the form of deep-space satellite exploration.

katovenus [111]4 years ago

6 0

Answer:

appears to be moving back toward unmanned exploration in the form of deep-space satellite exploration.

Explanation:

NASA moved from unmanned probing of space in its initial stage of space exploration to manned space exploration and moon landing and now has gone back to unmanned exploration into deeper space. Deep space is not completely known yet, and the exploration take year and are probably very dangerous for manned exploration for now.

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An 8 oz. bottle of energy drink contains 6.0 g of protein, 2.0 g of fat, and 16.3 g of carbohydrate. The fuel value of this ener

valina [46]

Answer: The correct option is d) 460 kJ

Explanation:

We are given:

Content of fat in energy drink = 2.0 g

Content of protein in energy drink = 6.0 g

Content of carbohydrate in energy drink = 16.3 g

Also,

The fuel value of fat = 38 kJ/g

The fuel value of protein = 17 kJ/g

The fuel value of carbohydrate = 17 kJ/g

So, the fuel value of the energy drink will be:

Total fuel value = $(2.0g\times 38 kJ/g)+(6.0g\times 17 kJ/g)+(16.3g\times 17 kJ/g)$

Total fuel value = $[76+102+277]=460kJ$

Hence, the correct option is d) 460 kJ

4 0

3 years ago

What is the reason atoms share electrons

kondaur [170]

Answer:

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5 0

3 years ago

Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur

Alenkinab [10]

Answer:

$\large \boxed{\text{-10.0 kJ}}$

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

$w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}$