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3 years ago

What are the coefficients?

Chemistry

1 answer:

jenyasd209 [6]3 years ago

5 0

The numbers in front of the formulas

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What has 39 neutrons which element

Rasek [7]

No of Neutrons =Mass No-No of protons

Proton=Neutron+1

$\\ \sf\longmapsto x+1=39$

$\\ \sf\longmapsto x=39-1=38$

Hence it has atomic no 38

The element is Stroncium(Sr)

6 0

2 years ago

Create a chemical equation for "Bubbling chlorine gas through a solution of sodium bromide gives elemental bromine and a solutio

Alexxandr [17]

Answer:

$Cl_{2} +2NaBr ---> 2NaCl + Br_{2}$

Explanation:

5 0

2 years ago

A sample of phosphorus-32 has a half-life of 14.28 days. If 55 g of this radioisotope remain unchanged after approximately 57 da

Flura [38]

55= No (1/2)^55/57
55= No (1/2)^3.9
55= No (1/2)^4
55= No (1/16)
No= 880 g

7 0

3 years ago

Read 2 more answers

Which of the following two combinations of reactants is more appropriate for the preparation of p-nitrophenyl phenyl ether? Fluo

VladimirAG [237]

Answer:

p-fluoronitrobenzene and sodium phenoxide is more appropriate

Explanation:

An ipso substitution is required to form p-nitrophenyl phenyl ether.

For this ipso substitution, an alkoxide anion needs to attack as a nucleophile at the carbon atom attached to fluorine atom and thereby substitute that F atom.

p-nitrophenoxide is an weak nucleophile as compared to phenoxide due to presence of electron withdrawing resonating effect of nitro group at para position.

p-fluoronitrobenzene is a good choice for nucleophilic attack by alkoxide anion as compared to fluorobenzene due to higher positive charge density at carbon atom directly attached to F atom. Higher positive charge density arises due to presence of electron withdrawing resonating effect og nitro group at para position.

So, p-fluoronitrobenzene and sodium phenoxide is more appropriate

5 0

3 years ago

A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t

777dan777 [17]

The molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = $\frac{A}{cl}$