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Yuliya22 [10]
3 years ago
11

A student’s work is shown below.

Mathematics
2 answers:
omeli [17]3 years ago
8 0

Answer:  Choice C

The student solved the problem incorrectly. The student should add 12.7 to both sides of the equation to isolate the variable, y.

================================================

Explanation:

We add 12.7 to both sides to undo the "minus 12.7"

We apply the inverse operation to whatever is happening to x.

As another example, solving x-2 = 10 leads to x = 12 after adding 2 to both sides to undo the "minus 2".

------------

The student's steps should look like this

y - 12.7 = 32.75

y-12.7+12.7 = 32.75+12.7

y = 45.45

Notice on the left side of the second step, we have the -12.7+12.7 become 0 and go away.

olga55 [171]3 years ago
7 0

Answer:

the correct answer is

D the student solved the problem. correctly

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To find the volume of this one we need to break it down 
now i see half of a cylinder and rectangle:)
but first lets find the volume of the rectangle...
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lets solve:)
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or we write it like this 
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now time to find the volume of the half cylinder:)
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3 0
3 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
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Answer: 2 meters.

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Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = 2w+15

width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0
3 years ago
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