a shape is randomly selected from the following quadrilaterals: parallelogram, rhomus, trapaziod, rectangle, square. what is pro
1 answer:
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Answer:
AB ≈ 14.3
Step-by-step explanation:
We're given <em>two sides </em>(BC and CA) and an <em>angle </em>(C)<em> between them</em>; the <em>law of cosines </em>is a good tool for calculating the third side of the triangle here. To remind you, the law of cosines tells us the relationship between the sides of a triangle with side lengths a, b, and c:
Where C is the angle between sides a and b. c is typically the side we're trying to find, so on our triangle, we have
Substituting these values into the law of cosines:
Answer:
(-3, 5), (-1, -1), (5, -3)
Step-by-step explanation:
Each pair of vertices can be one of the diagonals. Then the missing point will be found at the coordinates that are the sum of those, less the coordinates of the third point.
Given points are ...
A(-2, 2), B(1, 1), C(2, -2)
For AB a diagonal, D1 is ...
A+B-C = (-2+1-2, 2+1-(-2)) = (-3, 5)
For AC a diagonal, D2 is ...
A+C-B = (-2+2-1, 2-2-1) = (-1, -1)
For BC a diagonal, D3 is ...
B+C-A = (1+2-(-2), 1-2-2) = (5, -3)
_____
For a lot of parallelogram problems I find it easiest to work with the fact that the diagonals bisect each other. This means they both have the same midpoint, so for quadrilateral ABCD, we have (A+C)/2 = (B+D)/2. Multiplying this by 2 gives the equation we used above, A+C = B+D, so D=A+C-B. Remember, in ABCD, AC and BD are the diagonals.
