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FromTheMoon [43]
3 years ago
8

Question in screenshot please help!

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0
X^2 = 20(40) 
x^2 = 800
x = 20<span>√2

y^2 = 20(60)
y^2 = 1200
y = </span>20√3

z^2 = 40(60)
z^2 = 2400
z = 20√6
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Explain how to form a linear combination to eliminate the variable y for this system. 2x - 3y = 3 5x + 2y = 17A)Multiply the fir
jonny [76]
We aer goint to eliminate the x's
multiply first by -5 and 2nd by 2
so that is B
7 0
4 years ago
Simplify. (-7y^2+4y+9)+(6y^2-5y+9)-(2y^2-9y-2)
Natali5045456 [20]

Combine like terms

-7y² + 6y² - 2y² = -3y²

4y + (-5y) - (-9y) = 4y - 5y + 9y = 8y

9 + 9 - (-2) = 9 + 9 + 2 = 20

-3y² + 8y + 20 is your answer

hope this helps

7 0
3 years ago
what is an equation in the point-slope form of the line that passes through (-3,-1) and has a slope of 2?
LuckyWell [14K]

Answer:

well it would have to be y=2x-3

Step-by-step explanation:

yup

4 0
3 years ago
A bakery recorded the number of muffins and bagels it sold for a seven day period. For the data presented, what does the value o
atroni [7]

Answer:

Mean of bagel

Step-by-step explanation:

Working out each of the statically summaries Given in the option :

Mean of muffin :

Mean = Σx / n

n = sample size

(61 + 20 + 32 + 58 + 62 + 61 + 56) / 7

= 350 / 7

= 50

Mean of bagel :

Mean = Σx / n

n = sample size

(34 + 45 + 43 + 42 + 46 + 72 + 75) / 7

= 357 / 7

= 51

Hence, from the result obtained, we could see that the value of 51 summarizes the mean of bagel.

3 0
3 years ago
PLEASE HELP WITH 1-3 ILL MARK U THE BRAINLIEST
sammy [17]

Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

4 0
3 years ago
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