Area of the figure
= (area of rectangle) + (area of triangle)
= (8 × 10) + (½ × 4 × 8)
= 80 + 16
= 96
Area = 96ft²
Quarts of paint needed
= 96/22
= 48/11
= 4.36
Mr. Chen will have to buy 5 quarts of paint.
51/100
Explain: you start with 51/100 and that can’t be simplified any further :) hope this helped
Answer:
y-3 = 2x
2x-y+3=0 we have
slope
m =- coefficient of x/coefficient of y=-2/-3=2/3 is a slope..
Left 4 and up 1. x means left and right , y means up and down. x-4 would be left 4, y+1 would be up 1. :)
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let
be the random variable that follows a Poisson distribution, then mean ![\mu = \dfrac{10}{500}= 0.02](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cdfrac%7B10%7D%7B500%7D%3D%200.02)
and the mean that the random selection of 50 pages will contain no error is ![\lambda = 50 \times 0.02 =1](https://tex.z-dn.net/?f=%5Clambda%20%3D%2050%20%5Ctimes%200.02%20%3D1)
∴
![Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}](https://tex.z-dn.net/?f=Pr%28q%3D%200%29%20%3D%20%5Cdfrac%7Be%5E%7B-1%7D%20%281%29%5E0%7D%7B0%21%7D)
Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
![P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B%20%5Cdfrac%7Be%5E%7B-1%7D%201%5E0%7D%7B0%21%7D%20%2B%5Cdfrac%7Be%5E%7B-1%7D%201%5E1%7D%7B1%21%7D%20%5D)
![P(X \geq 2) = 1 - [0.3678 +0.3678]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B0.3678%20%2B0.3678%5D)
![P(X \geq 2) = 1 -0.7356](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-0.7356)
P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644