Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
10 percent
Step-by-step explanation:
- Before 1997, people with a minimum FBGL of 140mg/dl were diagnosed as diabetic
- After 1997, people with a minimum FBGL of 126mg/dl were diagnosed as diabetic
- What is the proportion of people who were not considered diabetic before 1997 but are now considered diabetic (after 1997)?
140 - 126 = 14
In percentage, this proportion is = 14/140 × 100
= 10%
Hence, 10% of the people who were not considered diabetic before 1997 are now or will now be considered diabetic.
Give me a min i need to think but ill get back to you as soon as possible
Answer:
x=5
y=2
Step-by-step explanation:
5x + 3y= 31
-6x - 3y = -36 (multiple by -3)
-x=-5
x=5
2(5)+y=12 or 25 + 3y= 31
10+y=12 3y=6
y=2 y=2
