<span>You need to find the path difference. That is, how much further must sound waves from the more distant speaker travel than the close speaker, to reach the mike.
Use Pythagoras to find the distance of the further speaker: it is √(2.00²+4.50²)=4.924m so the path difference is 4.924-4.50=0.424m.
You will get constructive interference when this path difference is an integer number of wavelengths, because the waves will arrive at the mike in phase.
The speed of sound is 340m/s so the lowest frequency that will produce an antinode at the mike is the one that makes 0.424=λ
v=fλ so f=v/λ
f=340/0.424=801Hz.
The next one will be when 0.424m = 2λ => λ=0.212m
f=340/0.212=1602Hz
and so-on according to f=340n/0.424 where n is an integer.
For destructive interference the path difference must be (n-½)λ because that will make the waves arrive at the mike 180° out of phase.
f=340(n-½)/0.424</span>
Answer:
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Explanation:
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Answer:
A) Workdone = 223.57 N-m
B) 22357 J of energy
C) Number of donuts = 10.7 donuts
Explanation:
A) The work done is calculated from the formula;. Work done = Force × Distance
We are given;
Mass; m = 43 kg
Distance = 0.53 m
Force(weight) = mg = 43 × 9.81
Thus;
Work done = 43 × 9.81 × 0.53
Workdone = 223.57 N-m
B) We are told she does 23 repetitions a day.
Thus, we assume 23% efficiency.
So, Work = Energy
Thus;
At 100% efficiency;
Energy = (223.57/100%) × 23 repetitions = 5142.11 J
Now, since she is only 23% efficient, she will expend; 5142.11/0.23 J = 22357 J of energy to do 5390 J of work.
C) from conversions; 4.18 J = 1 calorie
Thus;
22357 J ÷ 4.18 J/cal = 5348.565 calories
We how many 500 calorie donuts she can eat in a day to supply that energy.
Thus;
Number of donuts = 5348.565 cal ÷ 500 cal /donut
Number of donuts = 10.7 donuts
The force (weight) due to the hanging mass is
F = mg
where
m = mass, kg
g = 9.8 m/s²
The cross sectional area of the wire is
A = (π/4)*(0.43×10⁻³ m)² = 1.4522×10⁻⁷ m²
The stress in the wire is
σ = F/A = (9.8m N)/(1.4522×10⁻⁷ m²) = 6.7484x10⁷m Pa
The length of the wire is 2.1 m and the extension is 1.5 mm. Therefore the induced strain is
ε = (1.5x10⁻³ m)/(2.1 m) = 7.1429x10⁻⁴
By definition, Young's modulus is E = σ/ε. Therefore
(6.7484x10⁷m Pa)/(7.1429x10⁻⁴) = 20x10¹⁰ Pa
9.4477x10¹⁰m = 20x10¹⁰
m = 2.117 kg
Answer: 2.12 kg (to two sig. figures)
Answer: hockey
Explanation: cus it goateed