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MArishka [77]
3 years ago
14

Water from a fire hose is directed horizontally against a wall at a rate of 58.1 kg/s and a speed of 43.5 m/s. Calculate the mag

nitude of the force exerted on the wall (in N), assuming the water's horizontal momentum is reduced to zero.
Physics
1 answer:
Umnica [9.8K]3 years ago
4 0

Answer:

F = -2527.35 N

Explanation:

Given,

mass per unit time = 58.1 Kg/s

Speed of the water = 43.5 m/s

Final momentum = 0 kg/s

Force = Change in momentum

F = Final momentum - initial momentum

F = 0 - initial momentum

F = 0 -58.1\times 43.5

F = -2527.35 N

Hence, the Force exerted is equal to F = -2527.35 N

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Read 2 more answers
A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field a
Galina-37 [17]

Answer:

E   = (0.56 \times 10^8 ) r   \   \ N/c

Explanation:

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To find  the electric field for r < R by using Gauss Law

{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)

For r < R

Q_{enclosed}=(\rho) ( \pi r^2 ) l

E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}

E= \dfrac{\rho ( r)}{2 \varepsilon_o}

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\varepsilon_o = 8.85 \times 10^{-12}

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