Question

Water from a fire hose is directed horizontally against a wall at a rate of 58.1 kg/s and a speed of 43.5 m/s. Calculate the magnitude of the force exerted on the wall (in N), assuming the water's horizontal momentum is reduced to zero.

Answer 1

Answer:

F = -2527.35 N

Explanation:

Given,

mass per unit time = 58.1 Kg/s

Speed of the water = 43.5 m/s

Final momentum = 0 kg/s

Force = Change in momentum

F = Final momentum - initial momentum

F = 0 - initial momentum

$F = 0 -58.1\times 43.5$

F = -2527.35 N

Hence, the Force exerted is equal to F = -2527.35 N