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timofeeve [1]
3 years ago
14

पुस्तक विक्रेता ने वीपीपी द्वारा आपको पुस्तक भेजी है?? धन्यवाद देते हुए पत्र लिखिए।

Physics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

y e s :))))))))))))))))))))))))))))))))

Explanation:

y - dirdf leter of di alfabet

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Light can travel through outer space from the Sun to the Earth. This shows that
PIT_PIT [208]

Answer:

c. that light can travel in a vacuum

6 0
4 years ago
Two-out-of-tune flutes play the same note. One produces a tone that has a frequency of 250 Hz, while the other produces 266 Hz.
Andru [333]

Answer:

 x = 259 Hz

Explanation:

given,

frequency of one tuning fork = 250 Hz

frequency of another tuning fork = 266 Hz

when a tuning fork is sounded together beat frequency heard = 9

 let x be the frequency of unknown

 x - 250 = 9 Hz..............(1)

 x = 259 Hz

when a another tuning fork is sounded together beat frequency heard = 7

266 - x  = 7 Hz..............(2)

 x = 259 Hz

now, on solving both the equation the frequency comes out to be 259 Hz.

so, The frequency of the tuning fork is equal to 259 Hz

6 0
4 years ago
What are the steps to the scientific method
just olya [345]

Answer:

question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment

Explanation:

3 0
4 years ago
What is the momentum of a 4 kg object moving west at 4 m/s?*
Grace [21]

Answer:

16kg*m/s west

Explanation:

P=M*V

Momentum= Mass time velocity, plug it into the formula,

M is 4 and V is 4, 4*4=16, and since the object is moving west its going to be west.

basically saying in simpler terms,

16=4*4

4 0
3 years ago
A large aquarium of height 6 m is filled with fresh water to a depth of D = 1.50 m. One wall of the aquarium consists of thick p
Vesnalui [34]

Answer

given,

height of aquarium = 6 m

Depth of fresh water = D = 1.50 m

horizontal length of the aquarium(w) = 8.40 m

total force increased when liquid is filled to depth = 4.30 m

g = 9.81 m/s²

ρ = 998 Kg/m³

force in the aquarium.

dF = PdA

F = \int PdA

F = \int \rho\ g\ y\ (wdy)

F = \rho\ g\ w \int ydy

F = \rho\ g\ w\dfrac{y^2}{2}

F = \dfrac{\rho\ g\ w\ y^2}{2}

At D = 1.5 m

F = \dfrac{980\times 9.8\times 8.4\times 1.5^2}{2}

F = 9.08 x 10⁴ N

At D = 4.30 m

F = \dfrac{980\times 9.8\times 8.4\times 4.3^2}{2}

F = 7.46 x 10⁵ N

Total force on the wall increased by

ΔF  = 74.6 x 10⁴ - 9.08 x 10⁴

ΔF  = 65.52 x 10⁴ N

5 0
3 years ago
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