2 years ago

A uniform string of length 0.50 m is fixed at both ends. Find the

Physics

1 answer:

kozerog [31]2 years ago

4 0

Answer:

configuration of string:

Node - Antinode - Node or N-A-N

This is 1/2 wavelength since a full wavelength is N-A-N-A-N

f (fundamental) = V / wavelength

F0 = 300 m/s / 1 m = 100 / sec

F1 = 300 m/s / .5 m = 600 / sec

Each increase is a multiple of the fundamental since the wavelength

increases by 1/2 wavelength to keep nodes at both ends of the string

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