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vova2212 [387]
3 years ago
15

A uniform string of length 0.50 m is fixed at both ends. Find the

Physics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

configuration of string:

Node - Antinode - Node    or N-A-N

This is 1/2 wavelength since a full wavelength is N-A-N-A-N

f (fundamental) = V / wavelength

F0 = 300 m/s / 1 m = 100 / sec

F1 = 300 m/s / .5 m = 600 / sec

Each increase is a multiple of the fundamental since the wavelength

increases by 1/2 wavelength to keep nodes at both ends of the string

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Answer:

1.65

Explanation:

The equation of the forces along the horizontal direction is:

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The force of friction can be written as F_f = \mu R (2), where

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The equation of forces along the vertical direction is

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since the bookcase is in equilibrium. Substituting (2) and (3) into (1), we find

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And solving for \mu,

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3 years ago
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Answer:

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