B² - 4ac
= 8² - 4*(-2)*(-9)
= 64 - 72
= -8
Let the length of rectangle be L and the width of rectangle be W.
Since length exceeds the width by 25 inches, length will be
L = W + 25
Now the perimeter, P, is given by
P = 2(L + W)
Substituting L = W + 25 in the above equation,
P = 2(W + 25 + W)
P = 2(2W + 25)
P = 4W + 50
But P = 86 inches
P = 4W + 50 = 86
4W = 86 - 50 = 36
W = 36/4 = 9
Hence, width W = 9 inches.
Length L = W + 25 = 9 + 25 = 34 inches.
Its d 20 / (1+4)...........................................................................
