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Gwar [14]
3 years ago
7

Two integers, a and b, have different signs. The absolute value of integer a is divisible bu the absolute value of integer b. Fi

nd two integers that fit this description. Then decide if the product of the integers is greater than or less than the quotient of the integers. show your work

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

Step-by-step explanation:

see attached

You might be interested in
Which inequality is NOT true if y= -5?
Mila [183]

Answer: A

Step-by-step explanation:

2y - 10 > 13 y = -5

2(-5) - 10 > 13

-10 - 10 > 13

-20 > 13

False

3 0
2 years ago
6. Which interval represents the range of the function h(x) = 2x2 – 2x - 4?
lorasvet [3.4K]

Answer:-4.5,00

Step-by-step explanation:

6 0
3 years ago
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
A restaurant used 8 1/4 pounds of carrots to make 6 carrot cakes. Frank wants to use the same recipe. How many pounds of carrots
snow_tiger [21]

Answer:

To make one carrot cake 1 pound(approximately) carrot needed.

Step-by-step explanation:

Given:

8 1/4=33/4 pounds of carrots used to make 6 carrot cakes.

So, to get one carrot cake:

6 carrot cakes need = \frac{33}{4}

1 carrot cake need =  \frac{33}{4} ÷ 6

                               = \frac{33}{24}

                               = 1.375\ pound

Therefore, to make one carrot cake 1 pound(approximately) carrot needed.

4 0
3 years ago
Daily income of 8 workers is Rs. 2400. How many workers will earn Rs.1800
ValentinkaMS [17]

Answer:

6 workers

Step-by-step explanation:

Number workers to earnings is direct proportion.

8: 2400 :: x : 1800

Product of means = Product of extremes

2400 * x = 8*1800

           x = \frac{8*1800}{2400}\\\\x=6

4 0
3 years ago
Read 2 more answers
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