Answer:
Yes, Mina is correct
Step-by-step explanation:
Let the triangles be A and B
Given
Triangle A:
Triangle B:
Required
Is Mina's claim correct?
First, we calculate the third angle in both triangles.
For A:
For B:
For triangle A, the angles are: 34, 57 and 89
For triangle B, the angles are: 34, 57 and 89
<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>
Answer: Choice C) 10.5
The distance from A to C is 7 units (count out the spaces between the two points, or subtract y coordinates 4-(-3) = 4+3 = 7)
Let AC = 7 be the base of the triangle. You might want to rotate the image so that AC is laying horizontally rather than being vertical.
Now move to point P. Walk 3 spaces to the right until you land on segment AC. This shows that the height of the triangle is 3 when the base is AC = 7.
base = 7, height = 3
area of triangle = (1/2)*base*height
area of triangle = 0.5*7*3
area of triangle = 10.5 square units
2^t =38
take the log of each side
log ( 2^t) = log (38)
the exponent gets multiplies
t log (2) = log (38)
divide by log 2
t = log(38)/log (2)
t≈5.2479
Answer:
The one you are or were about to pick is correct.
Step-by-step explanation:
Answer:
y=2x+3
Step-by-step explanation:
The coefficient has to be 2, since the graph has a slope of 2, and the constant has to be 3 because the y- intercept is 3.
y=2x+3
