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const2013 [10]
3 years ago
11

Prove the following 1- sin A sin (90-1)/cot (90-a)= sin^2 A

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Im going to assume its (90 - A) so we have:-

1 - sinA sin (90 - A) / cot (90 - A)

Convert to sines and cosines:-

= 1 - (sin A cos A) / cos ( 90 - A) / sin ( 90 - A)

= 1 - (sin A cos A) / sin A / cos A

= 1 - cos^2 A

= sin^2 A which is what is required.


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At 5 oclock 5pm just do trial and error
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4 years ago
Write as a polynomial: <br><br> 2a^2(a-1)(3-a)
seropon [69]

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-2a^4+8a^3-6a^2

Step-by-step explanation:

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3 years ago
A group of students went to the fast-food restaurant after a game. They each ordered a 6-pc nugget entrée and a garden salad tra
marishachu [46]
I’m guessing you want to find out (n).
That’s what I did anyway.

The answer is: n=5

Step 1: Subtract 5n from both sides.
3.2
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=
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+
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Step 2: Subtract 9 from both sides.
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+
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Step 3: Divide both sides by -1.8.
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1.8
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1.8
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−
9
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7 0
3 years ago
Simplify the expression |12-5|-(6/2+1)^2
Zielflug [23.3K]

Answer:

-9

Alternative form:

-3^{2}

----------------------------------------------------

Steps:

1- Cross out the common factor

2- Calculate the sum or difference

3- Calculate the absolute value

4- Calculate the power

5- Calculate the sum or difference

5 0
2 years ago
Zaria wants you to solve this puzzle: “I am thinking of a number. If you divide my number by 2 and subtract 4, you will get 2. W
ycow [4]
Your answer should be 12 because you would take 2 ( because that is the ending number) and add 4. Then multiply by 2 and it is 12.
    step 1)  2+4=6
    step 2) 6 x 2=12
    step 3) 12=12 you're answer
6 0
4 years ago
Read 2 more answers
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