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Viktor [21]
2 years ago
8

Is Y=1/4x-1 Y=1/4x-1 No solution?

Mathematics
1 answer:
Romashka [77]2 years ago
5 0

Answer:

all solutions

Step-by-step explanation:

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Find A10 where<br> A-<br> ܢ<br> (<br> 1-2<br> 8<br> 0 -1 0<br> 0_0 -1
trasher [3.6K]

Answer:

worng question

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6 0
2 years ago
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
Can some one help on 30? thx
MariettaO [177]
The lowest common multiple of 2 and 7 is 14, so 14 days will pass before he does both chores again. 
5 0
3 years ago
Read 2 more answers
Please help me with this
kaheart [24]

Answer:

m9 = 115

m4 =110

m10=65

m11= 70

m8= 70

m5 = 65

m3 = 70

m14 = 115

4 0
2 years ago
Please help with both questions, thank you!
algol [13]

11) 3 (2x + 7) - 4 = 53 - 3x is the given

Then, we use distributive property and get:

6x + 21 - 4 = 53 - 3x

Next, we combine like terms

6x + 17 = 53 - 3x

Then, we use the addition property of equality to add 3x to both sides.

9x + 17 = 53

We then use the subtraction property of equality to subtract 17 from both sides.

9x = 36

Finally, we use the division property of equality to divide 36 by 9, which isolates x.

x = 4

So, (In order) you have the: Given, Distributive Property, Combine Like Terms, Addition Property of Equality, Subtraction Property of Equality, and Division Property of Equality.

12) Please Note: This is an inequality problem. Which means we do not use the properties of equality. We'd use the properties of order. Properties of order are specific to inequalities, as the properties of equality are specific to the equations. They do not cross. As for your paper, I'm not sure why it says to use the properties of equality. I will be using the properties of order.

-7 (3 + 8x) + 5x ≤ 1 - 62x is the given

-21 - 56x + 5x ≤ 1 - 62x is distributive property

We then combine like terms

-21 - 51x ≤ 1 - 62x

Next, we use subtraction property of order to subtract 1 from each side.

-22 - 51x ≤ -62x

Then, we add 51x to each siding using the addition property of order

-22 ≤ -11

Lastly, we use the division property of order to divide 11 from both sides, which then gives us:

2 ≥ x

It becomes a positive because we're dividing 2 negatives, and we also turn the sign because we're dividing by negatives.

In order: Given, Distributive Property, Combine Like Terms, Subtraction Property of Order, Addition Property of Order, and Division Property of Order.

 

5 0
2 years ago
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