Answer:
D
Step-by-step explanation:
Set up to different integrals that match the endpoints
so in our case it would look like
![\int\limits^0_{-2} {x} \, dx +\int\limits^1_0 {x+1} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_%7B-2%7D%20%7Bx%7D%20%5C%2C%20dx%20%2B%5Cint%5Climits%5E1_0%20%7Bx%2B1%7D%20%5C%2C%20dx)
now it's just a matter of computing it
![\int\limits^0_{-2} {x} \, dx =x^2\\0^2-(-2)^2=4\\\int\limits^1_0 {x+1} \, dx =\frac{x^2}{2}+x\\\frac{1}{2}+1-0=\frac{3}{2}\\\frac{3}{2}+4=\frac{11}{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_%7B-2%7D%20%7Bx%7D%20%5C%2C%20dx%20%3Dx%5E2%5C%5C0%5E2-%28-2%29%5E2%3D4%5C%5C%5Cint%5Climits%5E1_0%20%7Bx%2B1%7D%20%5C%2C%20dx%20%3D%5Cfrac%7Bx%5E2%7D%7B2%7D%2Bx%5C%5C%5Cfrac%7B1%7D%7B2%7D%2B1-0%3D%5Cfrac%7B3%7D%7B2%7D%5C%5C%5Cfrac%7B3%7D%7B2%7D%2B4%3D%5Cfrac%7B11%7D%7B2%7D)
Answer:
t(15)+10=c
Step-by-step explanation:
t (t-shirts) times 15 (the cost of each shirt) plus 10 (the shipping cost)=total cost
1/3 of an hour = 20 minutes
8 hours = 480 minutes
So to find the number of periods we divide 480 by 20. Answer is 24
A(n) = 9 + (n - 1) * 8
2nd term....n = 2
A2 = 9 + (2 - 1)*8
A2 = 9 + 1 * 8
A2 = 9 + 8
A2 = 17 <==
4th term...n = 4
A4 = 9 + (4 - 1) * 8
A4 = 9 + 3 * 8
A4 = 9 + 24
A4 = 33 <==
11th term...n = 11
A11 = 9 + (11 - 1) * 8
A11 = 9 + 10 * 8
A11 = 9 + 80
A11 = 89 <==
We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8
P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625