Question

15. Find the force on an electron crossing a uniform magnetic field of intensity 0.5 T WILII

Answer 1

Answer:

F = 8.48 x $10^{-18}$ N

Step-by-step explanation:

The force on an electron in a magnetic field can be determined by;

F = qvB Sin θ

where: e is the electron, v is its velocity, B is the measure of the magnetic field, and θ is the angle of its path.

Thus,

q = -1.6 x $10^{-19}$ C

v = 106 m/s

B = 0.5 T

θ = $90^{o}$

So that,

F = 1.6 x $10^{-19}$ x 106 x 0.5

  = 8.48 x $10^{-18}$ N

The force on the electron crossing the uniform magnetic field is 8.48 x $10^{-18}$ N.