15. Find the force on an electron crossing a uniform magnetic field of intensity 0.5 T WILII
1 answer:
Answer:
F = 8.48 x N
Step-by-step explanation:
The force on an electron in a magnetic field can be determined by;
F = qvB Sin θ
where: e is the electron, v is its velocity, B is the measure of the magnetic field, and θ is the angle of its path.
Thus,
q = -1.6 x C
v = 106 m/s
B = 0.5 T
θ =
So that,
F = 1.6 x x 106 x 0.5
= 8.48 x N
The force on the electron crossing the uniform magnetic field is 8.48 x N.
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Answer:
a) 14960 bottles
b) 502 bottles
Step-by-step explanation:
Given that:
Mean (μ) = 24 ounces, standard deviation (σ) = 0.14 ounces
a) From empirical rule (68−95−99.7%) , 68% of the population fall within 1 standard deviation of the mean (μ ± 1σ).
Therefore 68% fall within 0.14 ounces of the mean
the number of bottle = 22,000*68% = 14960 bottles
b) To solve this we are going to use the z score equation given as:
where x is the raw score = 23.72
From the normal probability distribution table: P(X < 23.72) = P (Z < -2) = 0.0228
The number of rejected bottles = 22000 × 0.0228 = 502 bottles
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